Question

Please hurry. Solve the equation

Answer 1

The value of x is $5\sqrt[3]{25}$.

Solution:

Given expression is $-7=8-3 \sqrt[5]{x^{3}}$.

Switch both sides.

$8-3 \sqrt[5]{x^{3}}=-7$

Subtract 8 from both side of the equation.

$8-3 \sqrt[5]{x^{3}}-8=-7-8$

$-3 \sqrt[5]{x^{3}}=-15$

Divide by –3 on both side of the equation.

$\frac{-3 \sqrt[5]{x^{3}}}{-3} =\frac{-15}{-3}$

$\sqrt[5]{x^{3}}=-5$

To cancel the cube root, raise the power 5 on both sides.

$(\sqrt[5]{x^{3}})^5=(-5)^5$

$x^3=3125$

To find the value of x, take square root on both sides.

$\sqrt[3]{x^3}=\sqrt[3]{25}$

$x=5\sqrt[3]{25}$

Hence the value of x is $5\sqrt[3]{25}$.