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scoundrel [369]
3 years ago
11

Please hurry. Solve the equation

Mathematics
1 answer:
Lelu [443]3 years ago
5 0

The value of x is 5\sqrt[3]{25}.

Solution:

Given expression is -7=8-3 \sqrt[5]{x^{3}}.

Switch both sides.

8-3 \sqrt[5]{x^{3}}=-7

Subtract 8 from both side of the equation.

8-3 \sqrt[5]{x^{3}}-8=-7-8

-3 \sqrt[5]{x^{3}}=-15

Divide by –3 on both side of the equation.

$\frac{-3 \sqrt[5]{x^{3}}}{-3} =\frac{-15}{-3}

\sqrt[5]{x^{3}}=-5

To cancel the cube root, raise the power 5 on both sides.

(\sqrt[5]{x^{3}})^5=(-5)^5

x^3=3125

To find the value of x, take square root on both sides.

\sqrt[3]{x^3}=\sqrt[3]{25}

x=5\sqrt[3]{25}

Hence the value of x is 5\sqrt[3]{25}.

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