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Ksivusya [100]
2 years ago
5

[ BRAINLIEST TO CORRECT ] please answer

Mathematics
2 answers:
Katyanochek1 [597]2 years ago
5 0

Answer:

OK good job

Step-by-step explanation:

welcome free brainly pls??? bless u

LUCKY_DIMON [66]2 years ago
3 0

Answer:\

Free answer?

Step-by-step explanation:

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Suppose a jar contains 5 red marbles and 25 blue marbles. If you reach in the jar and pull out one marble at random, do not repl
dsp73

Answer:

Probability that event will have both red marbles will be 2.3% or 0.023.

Step-by-step explanation:

Given:

Total red marbles=5

Total blue marbles=25

Total number of marbles =30

To Find:

The probability that both are red without replacement of marbles.

Solution:

Now

Total sample space is 30 and total red marbles are 5

For a event that getting red marble probability is ,

=Total red marbles /total marbles.

=5/30

=1/6

So probability if getting red marble is 1/6

<em>Now for second chance there will be 4 red marbles remaining and 29 total marbles so,</em>

In second chance  probability if getting red marble will be

=total red marbles present/total marbles remaining

=4/29

Now ,

The required probability will be getting both at a time

i.e probability getting red AND red marble so here AND operator which means multiple both the probability.

Probability both will have red =1/6*4/29

=4/(29*6)=2/(29*3)

=0.022988

=0.023

=2.3 %

8 0
3 years ago
3 groups of how many tenths is 1.5
topjm [15]
Well its 1 and 5 tenths 
- 1.5 = 15 tenths
- 5 groups of 3 is the answer
because 5 x 3 = 15
5 0
3 years ago
Read 2 more answers
Please can you help me anything will help please
Bumek [7]

Answer: 1, 2, 4, or 5

Step-by-step explanation:

The relationship in #3 is a function because all the x values are distinct, that is, none are repeated. (Y values don't matter.)

A function will not repeat any x values so if your goal is for the relationship in #4 to NOT be a function, repeat one of the x values. Any one will work.

4 0
3 years ago
Solve the equation in the complex number system.
tatiyna
To get rid of x^{3}, you have to take the third root of both sides:
\sqrt[3]{x^{3}} = \sqrt[3]{1}
But that won't help you with understanding the problem. It is better to write x^{3}-1 as a product of 2 polynomials:
x^{3}-1 = (x-1)\cdot (x^{2} +x +1)
From this we know, that x-1 = 0 => x = 1 is the solution. Another solutions (complex roots) are the roots of quadratic equation.
3 0
3 years ago
Read 2 more answers
Jeffery is playing a game with two spinners below:
Mrrafil [7]

The <em>correct answer</em> is:


{3, 4, 5, 6, 7, 8, 9, 10, 11, 12} .


Explanation:


The sample space for rolling these two spinners is:


(1, 2), (1, 4), (1, 6), (1, 8)

(2, 2), (2, 4), (2, 6), (2, 8)

(3, 2), (3, 4), (3, 6), (3, 8)

(4, 2), (4, 4), (4, 6), (4, 8)


This gives us the sums:

3, 5, 7, 9

4, 6, 8, 10

5, 7, 9, 11

6, 8, 10, 12


As a set, these are:

{3, 4, 5, 6, 7, 8, 9, 10, 11 12}

3 0
3 years ago
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