Can you completely over a 4 ft by 8 ft area with 3 ft by 3 ft tiles?

1 answer:

6 0

Yes, but not without cutting some of the tiles into smaller pieces.

The length of the area is 8-ft. That's (2 and 2/3) tiles long.

The width of the area is 4-ft. That's (1 and 1/3) tiles wide.

So you can't just put down rows and columns of whole tiles
and cover the whole area.
______________________________________

Another way to look at it:

-- The area of the whole big plot is (8 x 4) = 32 square feet.

-- Each tile covers (3 x 3) = 9 square feet.

-- You can't cover 32 square feet with 9-square-feet pieces.
Either you have to cut something off, or else you have to let
something hang outside of the lines.

You might be interested in

A. 1 and 8 <br> B. 4 and 6<br> C. 5 and 6<br> D. 1 and 7 <br> Please tell me why

andre [41]

1 and 7 because they have the same angles

6 0

3 years ago

A hemisphere fake stone made of clay has a diameter of 16 inches. The density of clay is 0.0035 pounds per cubic inch. The clay

Rufina [12.5K]

Answer:

$137.82

Step-by-step explanation:

The volume of a hemisphere stone is given by the volume of a half-sphere:

Volume = (2/3) * pi * radius^3

If the diameter is 16 inches, the radius is 16/2 = 8 inches, so the volume is:

Volume = (2/3) * pi * 8^3 = 1072.33 in3

We need a total of 8 stones, so the total volume is:

Total Volume = 8 * 1072.33 = 8578.64 in3

The density of clay is 0.0035 pounds per cubic inch, so the total weight of the 8 stones is:

Weight = Total Volume * density = 8578.63 * 0.0035 = 30.0252 pounds

Finally, if the price of each pound of clay if $4,59, the final price is:

Price = 30.0252 * 4.59 = $137.82

8 0

3 years ago

Find the exact value of sin2 theta given sin theta =5/13, 90°<theta <180°

Zepler [3.9K]

Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{13}}\impliedby \textit{now let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm\sqrt{13^2-5^2}=a\implies \pm\sqrt{144}=a\implies \pm 12 =a \implies \stackrel{II~quadrant}{-12=a}
\\\\\\
therefore \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{-12}}{\stackrel{hypotenuse}{13}}
\\\\
-------------------------------\\\\
sin(2\theta )\implies 2sin(\theta )cos(\theta )\implies 2\left(\frac{5}{13} \right)\left( \frac{-12}{13} \right)\implies -\cfrac{120}{169}$

3 0

3 years ago

How many solutions does this equation have?

Leto [7]

Answer:

The given equation having only one solution i.e., "w = 3". A further explanation is provided below.

Step-by-step explanation:

The given equation is:

⇒ $9(w-9)-2=-7w+7(w-8)$