Answer:
x = 48
Step-by-step explanation:
log〖 (2x+4)〗=2
Raise each side to the base of 10
10 ^log〖 (2x+4)〗=10^2
The 10 ^log cancels
2x+4 = 100
Subtract 4 from each side
2x+4-4 = 100-4
2x = 96
Divide by 2
2x/2 = 96/2
x =48
If <em>a</em> is fixed and <em>b</em>,<em>c</em> are unknowns then the equation <em>b</em>+<em>c</em>=10-<em>a</em> has 11-<em>a</em> solutions. They are pairs (b,c): (0,10-a), (1,9-a), (2,8-a), ... (10-a,0). As <em>a</em> runs from 0 to 10 we have total number of solutions (11-0)+(11-1)+...(11-1)=11+10+...+1=(1+11)*11/2=66.
Answer: 
<u>Step-by-step explanation:</u>
Think of the products row by row:
11 12 13 14 15 16 - 0 products greater than 6
21 22 23 24 25 26 - 3 products greater than 6
31 32 33 34 35 36 - 4 products greater than 6
41 42 43 44 45 46 - 5 products greater than 6
51 52 53 54 55 56 - 5 products greater than 6
61 62 63 64 65 66 - 5 products greater than 6

Answer:
x = 12
Step-by-step explanation: