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RideAnS [48]
4 years ago
10

HELP WITH 12 PLZ???!?!?!?!!!!?

Mathematics
2 answers:
Snezhnost [94]4 years ago
7 0

You only showed half of the question how can we answer that?!

dezoksy [38]4 years ago
3 0

Can you show the full question?

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Christine went on a passenger train that traveled 80 miles in one hour. How many miles will it travel in six hours?
zhuklara [117]

Answer:

480

Step-by-step explanation:

80*6 = 480

8 0
2 years ago
Read 2 more answers
1a.) Given the equation 5+ 6n-4n-15, explain how to get the answer n10.
Savatey [412]

Answer:


Step-by-step explanation:

combine like terms (6n-4n)=(5-15)

2n=-20

n=20/2

n=10

7 0
3 years ago
How many distinct prime factors are in the number 120 ?
larisa86 [58]

Answer:

3.

Step-by-step explanation:

Note the prime factorization of 120,

120=2^3\times 3\times 5

Therefore, there are 3 distinct prime factors, namely 2, 3 and 5.

8 0
3 years ago
Let theta be an angle in quadrant II such that cos theta = -2/3
Iteru [2.4K]

Answer:

So we have \csc(\theta)=\frac{3 \sqrt{5}}{5} \text{ and } \tan(\theta)=\frac{-\sqrt{5}}{2}.

Step-by-step explanation:

Ok so we are in quadrant 2, that means sine is positive while cosine is negative.

We are given \cos(\theta)=\frac{-2}{3}(\frac{\text{adjacent}}{\text{hypotenuse}}).

So to find the opposite we will just use the Pythagorean Theorem.

a^2+b^2=c^2

(2)^2+b^2=(3)^2

4+b^2=9

b^2=5

b=\sqrt{5}  This is the opposite side.

Now to find \csc(\theta) and \tan(\theta).

\csc(\theta)=\frac{\text{hypotenuse}}{\text{opposite}}=\frac{3}{\sqrt{5}}.

Some teachers do not like the radical on bottom so we will rationalize the denominator by multiplying the numerator and denominator by sqrt(5).

So \csc(\theta)=\frac{3}{\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}}=\frac{3 \sqrt{5}}{5}.

And now \tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}=\frac{\sqrt{5}}{-2}=\frac{-\sqrt{5}}{2}.

So we have \csc(\theta)=\frac{3 \sqrt{5}}{5} \text{ and } \tan(\theta)=\frac{-\sqrt{5}}{2}.

7 0
3 years ago
Read 2 more answers
Georgina was given that the length of the rectangle was 2.5 inches longer than its width, and that the perimeter of the rectangl
Troyanec [42]

Answer: length = 20.1

Width=17.6

Step-by-step explanation:

4 0
3 years ago
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