<h3>1) <u>What is the solution for the system of equations</u></h3>
-2x+y=2...(i)
y=4x-1...(ii)
substitute y in (i)
-2x+(4x-1)=2
-2x+4x-1=2
-2x+4x=2+1
2x=3
2x/2=3/2
x=3/2
replacing x in (ii)
y=4(3/2)-1
y=6-1
y=5
solution=(3/2,5)
<h3 /><h3>2) <u>Solve the system of equations.</u></h3>
x-y+z=6 ...(i)
4y+1=z ...(ii)
3y=2z...(iii)
from(ii),
z=4y+1
substitute z in (iii)
3y=2(4y+1)
3y=8y+2
3y-8y=2
-5y=2
-5y/5=2/5
y=-2/5
substitute y in (ii)
z=4(-2/5)+1
z=-3/5
substitute z and y in (i)
x-y+z=6
x=6+y-z
x=6+(-2/5)-(-3/5)
x=31/5
solution=(31/5,-2/5,-3/5)
<h3>
3) <u>What is the solution for the system of equations</u></h3>
-4x+y=-2 ...(i)
y+5=-6x...(ii)
from (i),
y=-2+4x
substitute y in (ii)
(-2+4x)+5=-6x
-2+4x+5=-6x
-2+5=-6x-4x
3=-10x
3/-10=-10x/-10
x=-3/10
substitute x in;;y=-2+4x
y=-2+4(-3/10)
y=-2-6/5
y=-16/5
solution=(-3/10,-16/5)
Answer:
(-9.15)
Step-by-step explanation:
We are given these following vectors:
u = (2,4), v = (-1,-1), w = (7,-2)
What is the vector for 3u + v- 2w in component form?
3u + v - 2w = 3(2,4) + (-1,-1) - 2(7,-2) = (6,12) + (-1,-1) + (-14,4) = (6 - 1 - 14, 12 - 1 + 4) = (-9, 15)
The answer is (-9,15).
Answer:
1.→n=15
2.→n=0
Step-by-step explanation:
The two expressions given are
⇒A number is said to be rational if it can be expressed in the form of , where ,q≠0.And it's decimal expansion will be either terminating or non terminating repeating.
We have to find smallest value of n, for which each of these two expressions will be rational.
So, 1.→n=15
and 2.→n=0
Have a nice day! -Alpha