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nataly862011 [7]
3 years ago
10

I need to know the number in the blank box.​

Mathematics
2 answers:
kirza4 [7]3 years ago
4 0

Answer:

$1,530.00

Step-by-step explanation:

We know that the cost to manufacture 3 motorcycles is $4,590.00

The blank box represents the cost of one motorcycle.

Divide $4,590.00 by 3 to get the cost of 1 motorcycle

$4,590.00 ÷ 3 = $1,530.00

The cost to manufacture one motorcycle at the Kawahama factory is

$1,530.00

Hope this helps :)

Reika [66]3 years ago
3 0

Answer:

1530

Step-by-step explanation:

divide 4590 by 3.

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(4,0),(0,-12)

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What is the factored form of the polynomial below and find the zeros. *<br> 4x² + 5x – 6
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(4x-3)(x+2)

Step-by-step explanation:

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Is rolling doubles a simple event or compound event? Explain.<br><br><br> (rolling double dice)
nexus9112 [7]
You have to consider the sample space. In this example the sample space

is {1,2,3,4,5,6}

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Equally if you roll 2 dice and want to get "one" and/or "three" this is a compound event since you have chosen 2 outcome from the sample space.

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Read 2 more answers
A food-packaging apparatus underfills 10% of the containers. Find the probability that for any particular 10 containers the numb
Maksim231197 [3]

Answer:

a) P(X = 1) = 0.38742

b) P(X = 3) = 0.05740

c) P(X = 9) = 0.00000

d) P(X \geq 5) = 0.00163

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it is undefilled, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem

There are 10 containers, so n = 10.

A food-packaging apparatus underfills 10% of the containers, so p = 0.1.

a) This is P(X = 1)

P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742

b) This is P(X = 3)

P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740

c) This is P(X = 9)

P(X = 9) = C_{10,9}.(0.1)^{9}.(0.9)^{1} = 0.00000

d) This is P(X \geq 5).

Either the number is lesser than five, or it is five or larger. The sum of the probabilities of each event is decimal 1. So:

P(X < 5) + P(X \geq 5) = 1

P(X \geq 5) = 1 - P(X < 5)

In which

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.34868

P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742

P(X = 2) = C_{10,2}.(0.1)^{2}.(0.9)^{8} = 0.1937

P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740

P(X = 4) = C_{10,4}.(0.1)^{1}.(0.9)^{9} = 0.38742

So

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.34868 + 0.38742 + 0.19371 + 0.05740 + 0.01116 = 0.99837

Finally

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.99837 = 0.00163

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