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Leviafan [203]
3 years ago
12

PLZZ HELP ASAPP!!(Plz anwer em right!)

Mathematics
1 answer:
Shalnov [3]3 years ago
7 0

Answer:

2. D.) \displaystyle \frac{4}{3}

1. \displaystyle ?

Step-by-step explanation:

2.) Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE <em>RATE OF CHANGES </em>[<em>SLOPES</em>], so −¾ becomes 4⁄3.

1.) <em>No</em><em> </em><em>illustration</em><em> </em><em>provided</em>

Perhaps there was a typographical error?!

Though, I am still joyous to assist you.

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amal drew the function below. Which explains whether or not his function is linear? On a coordinate plane, a line with negative
SIZIF [17.4K]

Answer:

it is linear bc it has a constant rate of change

Step-by-step explanation:

6 0
3 years ago
Solve the equation 1-4n+1+3n
Elanso [62]


Explain

1 - 4n +1 +3n
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2-n
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(Divide by negative 1)
-2/1=n/-1

N=1
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3 years ago
Read 2 more answers
An online company lets you download songs for $1 each
siniylev [52]

Answer:$105

Step-by-step explanation:

I think but the way I done it was a 100 *1+5

7 0
3 years ago
A pilot can fly an airplane 2240 miles with the wind in the same time as she can fly 1920 miles against the wind. If the speed o
Artist 52 [7]
Recall your d = rt, distance = rate * time

so... hmm if the plane has a still air speed of say "r", when it's going with the wind, is not really going "r" fast, is going "r + 40 ", because the wind is adding 40mph to its speed, is really moving.

and when the plane is going against the wind, is not really going "r" fast either, is going " r - 40 ", because the wind is eroding speed from it.

now, it went 2240 miles for say "t" hours, and it did 1920 miles for the same length of time, "t" hours.

\bf \begin{array}{lccclll}&#10;&distance&rate&time\\&#10;&-----&-----&-----\\&#10;\textit{with the wind}&2240&r+40&t\\&#10;\textit{against the wind}&1920&r-40&t&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;2240=(r+40)t\implies \frac{2240}{r+40}=\boxed{t}\\&#10;1920=(r-40)t\\&#10;----------\\&#10;1920=(r-40)\left( \boxed{\frac{2240}{r+40}} \right)&#10;\end{cases}&#10;\\\\\\&#10;1920=\cfrac{(r-40)2240}{r+40}\implies 1920(r+40)=(r-40)2240&#10;\\\\\\&#10;1920r+76800=2240r-89600\implies 166400=320r&#10;\\\\\\&#10;\cfrac{166400}{320}=r

and surely you know how much that is.
6 0
3 years ago
Help please i need the answer​
Genrish500 [490]

Answer:

3x+4

Step-by-step explanation:

You can not add a variable number to a no variable number so just remove the parenthaseis.

Please tell me if I did well.

3 0
4 years ago
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