What is the slope of the line that is parallel to the line

1 answer:

6 0

Both slopes are going to be the same, as parallel lines have the same slopes but different y-intercepts. To find the slope of this line (if you haven’t already), you need to isolate y.

4x - 5y= -1

-5y= -4x - 1 (or -1 - 4x)

-y= (-4/-5)x - 1/5

Canceling out the negatives,
y= (4/5)x + 1/5.

Therefore, the slope of both the listed line and any line parallel to it is 4/5.

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Given that f(–2.4) = -1 and f(-1.9) = -8, approximate f'(-2.4). f'(-2.4)

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Answer:

f'(-2.4) ≈ -14

General Formulas and Concepts:
Algebra I

Coordinate Planes

Coordinates (x, y)

Slope Formula: $\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}$

Functions

Function Notation

Calculus

Differentiation

Derivatives
Derivative Notation

Step-by-step explanation:

*Note:

The definition of a derivative is the slope of the tangent line.

Step 1: Define

Identify.

f(-2.4) = -1

f(-1.9) = -8

Step 2: Differentiate

Simply plug in the 2 coordinates into the slope formula to find slope m.

[Derivative] Set up [Slope Formula]: $\displaystyle f'(-2.4) \approx \frac{f(x_2) - f(x_1)}{x_2 - x_1}$
Substitute in coordinates: $\displaystyle f'(-2.4) \approx \frac{-8 - -1}{-1.9 - -2.4}$
Evaluate: $\displaystyle f'(-2.4) \approx -14$