Can some one do these questions and show work please and thank you

Mathematics

2 answers:

EleoNora [17]3 years ago

8 0

Answer:

9) So basically we have what they all add up to and we have 2 of the sides out of 3 so what we can do is take the perimeter and minus the two sides we do know to get the one we dont know.

Set up:

10x+5y - (3x+4y) - (5x-y)

Remove parenthesees

10x+5y-3x-4y-5x+y

Simplify

2x+2y (ANSWER TO 9)

10) This one is giving us a triangle and we know all 3 sides. Its asking for that the perimeter is which is all of the sides added so we should add them.

Set up:

(3a+4) + (2a-7) + (5a^2 + a)

Group them together so we dont make mistakes

5a^2 + 3a+2a+a + 4-7

Simplify

5a^2 + 6a - 3 (ANSWER TO 10)

babymother [125]3 years ago

6 0

Answer:

9) 3rd side = 2x+2y

10) 5a^2 + 6a - 3

Step-by-step explanation:

9) 10x+5y - ( 3x+ 4y) = 7x + y

7x + y - ( 5x - y ) = 2x + 2y

10)

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Triangle QRS has vertices Q(-4,2),R(3,0), and S(4,3).

Dafna1 [17]

The coordinates of the vertices of $\triangle Q'R'S'$ are $Q'(x,y) = (0, -4)$ , $R'(x,y) = (7,-6)$ and $S'(x,y) = (8, -3)$ , respectively.

Vectorially speaking, a point is translated to another location on Cartesian plane by means of this expression:

$A'(x,y) = A(x,y) + T(x,y)$ (1)

Where:

$A(x,y)$ - Original point.
$A'(x,y)$ - Translated point.
$T(x,y)$ - Translation vector.

If we know that $Q(x,y) = (-4,2)$ , $R(x,y) = (3,0)$ , $S(x,y) = (4, 3)$ and $R'(x,y) = (7, -6)$ $T(x,y) = (4, -6)$ , then the coordinates of the vertices of the triangle $Q'R'S'$ are: