Answer:
a) Peterson International is a trenchcoat wholesaler to retailers around the world. Sixty percent of sales orders are taken during the months of August and September. Peterson needs a system to manage online ordering and fulfillment.
Explanation:
Outsourcing likely to be the best solution to the firm's data processing needs because Peterson International is a trenchcoat wholesaler to retailers around the world. Sixty percent of sales orders are taken during the months of August and September. Peterson needs a system to manage online ordering and fulfillment.
Answer:
Total Expense: $ 347,000
Income: $ 135,000
Explanation:
<u><em>Income Statement Imaging Services </em></u>
<u><em>For the Month Ended March 31, 2018</em></u>
Fees earned $482,000
Wages expense $ 300,000
Rent expense $41,500
Supplies expense $3,600
Miscellaneous expense $1,900
Total Expenses $ 347,000
Income $ 135,000 Wages, rent , supplies and miscellaneous expenses are totaled and deducted from the fees earned. Fee earned is the revenue and the expenses are deducted from it. By deducting expenses from revenue we get the income.
Answer:
Net cash provided from Operating Activities $301
Explanation:
MYRIAD PRODUCTS COMPANY
Cash flow from Operating Activities:
Net Income $150
Adjustment for non cash effects:
Depreciation $84
Amortization $5
Loss on sale of land $4
Total $243
Changes in operating assets and liabilities :
Decrease in Accounts receivable $17
Decrease in Inventory $18
Increase in Accounts Payable $14
Decrease in Salaries Payable ($14)
Increase in Interest Payable $13
Increase in Income tax Payable $10
Net cash provided from Operating Activities $301
Spending that goes into our national debt. Debt spending.
Answer:
a) 15 to 35 approximately 95%
(b) 10 to 40 approximately almost all
(c) 20 to 30 approximately 68%
Explanation:
The data have a bell-shaped distribution which means the data is equally distributed on both sides of the mean.
We have the mean at 25 and a standard deviation of 5 which means that the interval is for each of the values of 5 .
The mean would be u and
The first value would be u ±σ = 25 ± 5= 20 and 30 (68 % )
The second value will be u ± 2σ= 25± 10 = 15 and 35 (95%)
The third value will be u ± 3σ= 25 ± 15 = 10 and 40 (99.7 % almost all)
In the figure below the light blue region gives u ±σ on both sides of the mean
, dark blue gives u ± 2σ values on both sides of the mean and grey gives
u ± 3 σ values on both sides of the mean.
It is obvious that 68 % of the data is contained in the u ±σ light blue region, 95 % of the data in the u ± 2σ dark blue including light blue and 99.7 % in the u ± 3σ all colored regions.
