A line passes through the point (-10,8) and has a slope of 1/2.

Rearrange x = 7y - 5 to make y the subject.

nalin [4]

By rearranging x = 7y - 5 to make y the subject, we get

x + 5 = 7y ( By transposition method )

or, $\huge \purple {\tt {\frac{x + 5}{7} = y}}$

<h2>Answer:</h2>

$\huge \pink {\tt {y = \frac{x + 5}{7}}}$

3 0

3 years ago

At the local animal shelter, there are 35 cats and 42 dogs. What is the ratio of dogs to cats at the local animal shelter?

postnew [5]

9514 1404 393

Answer:

6 : 5

Step-by-step explanation:

The ratio is ...

dogs : cats = 42 : 35 = (7·6) : (7·5) = 6 : 5

The ratio of dogs to cats at the shelter is 6 to 5.

6 0

3 years ago

Also this stuff too I need it before my teach put grades in

andrew11 [14]

Answer:

1. Distance is 5 units 2. Distance is 14 units 3. B. (2, -5), 10. (4, 14) 11. (6, 12) 14. x = 12 16. x = 55

Step-by-step explanation:

6 0

3 years ago

Convert the unit<br>1.5kg to g

navik [9.2K]

Answer:

The answer should be 1500g I think.

6 0

3 years ago

Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex

bagirrra123 [75]

Answer:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

$\hat p=0.021$ estimated proportion of interest

$p_o=0.012$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:

Null hypothesis: $p \leq 0.012$

Alternative hypothesis: $p > 0.012$

When we conduct a proportion test we need to use the z statisitic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0

3 years ago