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3 years ago

Solve all and: (will give brainly QUICKLEY FOR BEST ANSWERS!!

Mathematics

2 answers:

My name is Ann [436]3 years ago

7 0

Answer:

Step-by-step explanation:

1) 6r - 12 + 6r + 11 = 11

Combine like terms

6r + 6r - 12 + 11 = 11

12r - 1 = 11

12r = 11 + 1

12r = 12

r =12/12

r = 1

2) 8m + 5 + 13m - 5 = 42

8m + 13m + 5 - 5 = 42

21m +0 = 42

21m = 42

m = 42/21

m = 2

3) 4x + 5 + 5x + 6 = 29

4x + 5x + 5 + 6 = 29

9x + 11 = 29

9x = 29 - 11

9x = 18

x = 18/9

x = 2

REY [17]3 years ago

7 0

Answer:

r = 1 m = 2 x = 2

Step-by-step explanation:

1. 6(1)-12+6(1)+11=11

2. 8(2)+5+13(2)-5=42

3. 4(2)+5(2)+6=29

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Can you help me please? explain why its a yes or no.

Rashid [163]

Answer: No

Step-by-step explanation: it’s a no because. 19 - 15 does not equal out to 7 19 - 15 is 4 and that’s the wrong answer for 19 -15

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2 years ago

CD is a perpendicular bisector of chord AB and a chord through CD passes through the center of a circle. Find the diameter of th

Keith_Richards [23]

Answer:

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Step-by-step explanation:

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2 years ago

A 2000 gallon fish aquarium can be filled by water flowing at a constant rate in 10 hours. When a decorativve rock is placed in

Elza [17]

Answer:

The volume of the rock is 13.368 cubic feet.

Step-by-step explanation:

The volume of the rock ( $V_{r}$ ), measured in gallons, is equal to the volume of the fish aquarium without the decorative rock ( $V'$ ) minus the volume of the fish aquarium with the decorative rock ( $V''$ ), both measured in gallons.

Since the water flow is at constant rate, the volume of the rock is expressed by the following equation:

$V_{r} = V' - V''$

$V_{r} = \dot V \cdot (\Delta t_{1}-\Delta t_{2})$ (1)

Where:

$\dot V$ - Flow rate, measured in gallons per hour.

$\Delta t_{1}$ - Filling time of the fish aquarium without the decorative rock, measured in hours.

$\Delta t_{2}$ - Filling time of the fish aquarium with the decorative rock, measured in hours.

And the flow rate is:

$\dot V = \frac{2000\,gal}{10\,h}$

$\dot V = 200\,\frac{gal}{h}$

The flow rate is 200 gallons per hour.

If we know that $\dot V = 200\,\frac{gal}{h}$ , $\Delta t_{1} = 10\,h$ and $\Delta t_{2} = 9.5\,h$ , then the volume of the rock is:

$V_{r} = \left(200\,\frac{gal}{h}\right)\cdot (10\,h-9.5\,h)$

$V_{r} = 100\,gal$

$V_{r} = 13.368\,ft^{3}$

The volume of the rock is 13.368 cubic feet.

8 0

3 years ago

The ratio of 1 to 3 is

andreev551 [17]

1:3 that's so easy like bruh

3 0

3 years ago

Read 2 more answers

8*11=(8*10)+(1*10) is the equation true

svet-max [94.6K]

Answer:

Step-by-step explanation:

8*10=80, 1*10=10

80+10=90

8*11=88

88 does not equal 90 so no

5 0

3 years ago

Read 2 more answers