Answer:
The triangle ABD and CBD are congruent.
Step-by-step explanation:
The requirement is that every element in the domain must be connected to one - and one only - element in the codomain.
A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.
So, the two things can't can't happen is that you don't have any arrow starting from a point in the domain, i.e. the function is not defined for that element, or that multiple arrows start from the same points.
But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.
Answer:
C. RTS
Step-by-step explanation:
When two triangles are congruent, they will have congruent vertices, like each vertex has a partner.
Take a look at the shape of the triangle.
If you look at the triangle on the right, you can see it is almost like a right triangle.
"R" is at the right angle. "S" is on the short side and "T" is on the long side.
In the triangle on the left, "M" is at the right angle. "N" is on the short side and "O" is on the long side.
Thus, the pairs of congruent angles are:
M ≅ R
O ≅ T
N ≅ S
When you write the statement of congruence between triangles, order the letters by their congruent pair.
MON ≅ RTS