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2 years ago

Write an expression for the sequence of operations: subtract 2 from c, then subtract 7 from the result

Mathematics

2 answers:

kipiarov [429]2 years ago

6 0

Answer:

Step-by-step explanation: (c-2)-7

Rainbow [258]2 years ago

6 0

Step by step you have to answer

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During the first decade of the century, the population of a certain city was 145,380 in 2000 and 219,135 in 2010. Find the expon

Likurg_2 [28]

Answer:

The exponential growth function is $P=145380e^{0.04103t}$

Step-by-step explanation:

Given: The population of a certain city was 145,380 in 2000 and 219,135 in 2010.

To find: exponential growth function that models the growth of the city

Solution:

The exponential growth function is given by $P=P_0 e^{kt}$

Here, P denotes total population after time t

$P_0$ denotes initial population

k denotes rate of growth

t denotes time

As $P(0)=145,380$ ,

$145380=P_0e^{0}\\145380=P_0\\P=145380e^{kt}$

As $P(10)=219135$

$219135=145380e^{10k}\\e^{10k}=\frac{219135}{145380}\\=1.507326\\k=\frac{1}{10}\ln (1.507326)\\=0.04103\\\Rightarrow P=145380e^{0.04103t}$

8 0

2 years ago

What is the justification for each step in solving the inequality? -5(4x+6<-18x+6+4x

Daniel [21]

Hi there!

Everything looks correct except for the step to get to -6x < 36. Here you put multiplication property of order, and to get here you have to add 30 to both sides, so it would actually be the addition property of order.

I hope I helped!

5 0

2 years ago

a rental car agency charges $210.00 per week plus $0.15 per mile to rent a car. how many miles can you travel in one week for $2

max2010maxim [7]

$291-$210=$81
$81/0.15= 540 miles
I believe the answer is 540 mi.

7 0

3 years ago

-2 (x- 1) <24

Fantom [35]

Yessssssssssssssssssss

4 0

3 years ago

A random sample of math majors taking an introductory statistics course were surveyed after completing the final exam. They were

quester [9]

Answer:

$E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8$

Now we can find the second moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4$

The variance would be given by:

$Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96$

And the deviation would be:

$Sd(X) =\sqrt{6.96}= 2.638$

Step-by-step explanation:

For this case we have the following distribution given:

X 1 2 7

P(X) 1/5 2/5 2/5

We need to begin finding the mean with this formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8$

Now we can find the second moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4$

The variance would be given by:

$Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96$

And the deviation would be:

$Sd(X) =\sqrt{6.96}= 2.638$

7 0

3 years ago