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2 years ago

Internet Pricing An Internet Service Provider (ISP) offers its customers three options:

Mathematics

1 answer:

Mama L [17]2 years ago

4 0

Answer:

(b)$29.62

(c)$5.73

Step-by-step explanation:

Basic: Standard internet for everyday needs, at $24.95 per month.

Premium: Fast internet speeds for streaming video and downloading music, at $30.95 per month.

Ultra: Super-fast internet speeds for online gaming at $40.95 per month.

Let the number of customers on Ultra=x; therefore:

Number of Premium customers =2x

Number of Basic customers =3x

Total=x+2x+3x=6x

$P(Ultra)=\dfrac{x}{6x}=\dfrac{1}{6} \\P(Premium)=\dfrac{2x}{6x}=\dfrac{1}{3}\\P(Basic)=\dfrac{3x}{6x}=\dfrac{1}{2}$

(a)X=Monthly fee paid by a randomly selected customer.

Therefore, the probability distribution of X is given as:

$\left|\begin{array}{c|c}X&P(X)\\---&---\\\$24.95&3/6\\\$30.95&2/6\\\$40.95&1/6\end{array}\right|$

(b)Average Monthly Revenue per customer

Mean,

$\mu=(\$24.95 \times 3/6)+(\$30.95 \times 2/6)+(\$40.95 \times 1/6)\\=\$29.62$

(c)Standard Deviation

$\left|\begin{array}{c|c|c|c|c}x&P(x)&x-\mu &(x-\mu)^2&(x-\mu)^2P(x)\\-----&-----&----&----&-----\\\$24.95&3/6&-4.67&21.8089&10.9045\\\$30.95&2/6&1.33&1.7689&0.5896\\\$40.95&1/6&11.33&128.3689&21.3948\\-----&-----&----&----&-----\\&&&&32.8889\end{array}\right|$

$\text{Standard Deviation}=\sqrt{(x-\mu)^2P(x)}\\=\sqrt{32.8889} \\ \sigma=\$5.73$

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Factor: m^2 - 20m - 21

Anton [14]

Answer: (m-21)(m+1)

Step-by-step explanation:

To factor this trinomial, find two numbers that multiply to -21 and add to -20:

(-21)(1)=-21

-21+1=-20

They are -21 and 1.

Add -21 and 1 to m to get both factors:

(m+(-21)) and (m+1)

(m-21) and (m+1)

Multiply them to get the answer:

(m-21)(m+1)

4 0

2 years ago

For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!

Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

$x^2-2x-(c+4)=0$ .

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic $ax^2+bx+d$ , the discriminant is $\sqrt{b^2-4ad}$ .

(The discriminant is more commonly known as $\sqrt{b^2-4ac}$ , but I changed the variable since we already have a $c$ in the quadratic given.)

In the quadratic above, we have $a=1$ , $b=-2$ , and $d=-(c+4)$ . Plugging this into the formula for the discriminant, we have

$\sqrt{(-2)^2-4(1)(-(c+4))$ .

Using the distributive property to expand and simplifying, the expression becomes

$\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.$