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jarptica [38.1K]
3 years ago
12

Point XXX is located at (3, 2)(3,2)left parenthesis, 3, comma, 2, right parenthesis. Point YYY is located at (3, -8)(3,−8)left p

arenthesis, 3, comma, minus, 8, right parenthesis. What is the distance from point XXX to point YYY?
Mathematics
2 answers:
NeX [460]3 years ago
7 0

Answer:

10

Step-by-step explanation:

Given that:

Point X = (3, 2)

Point Y = (3, - 8)

Distance of point X to Y:

Distance = √(x2 - x1)^2 + (y2 - y1)^2

X1 = 3 ; y1 = 2 ; x2 = 3 ; y2 = - 8

Distance = √(3 - 3)^2 + (-8 - 2)

Distance = √(0)^2 + (-10)^2

Distance = √0 + 100

Distance = √100

Distance = 10

Readme [11.4K]3 years ago
5 0

Answer:

10

Step-by-Step Explanation:

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Suppose that it snows in Greenland an average of once every 20 days, and when it does, glaciers have a 28% chance of growing. Wh
Svetach [21]

Answer:

14

Step-by-step explanation:

5 0
3 years ago
1/8 of pizza cost 2 dollars. In an hour, 6 1/4 pizzas were sold. How much money was made at the food booth in that hour
Darina [25.2K]
First of all, you would make 6 1/4 into an improper fraction. This makes it 25/4, then you multiply it by 2 to get 50/8 and have common denominators. Divide that by 1/8, which would be 50. Then since each 1/8 costs 2 dollars you would multiply 50 by 2. So, the answer would be that they made 100 dollars.
4 0
3 years ago
Grace invested $5,200 in an account paying an interest rate of 4.6% compounded daily. Assuming no deposits or withdrawals are ma
nlexa [21]

Answer:

Step-by-step explanation:

Use this formula for when compounding is either not continuous or is not annually:

A(t)=P(1+\frac{r}{n})^{(n)(t)} where P is the initial investment, r is the interest rate in decimal form, n is the number of times the compounding occurs per year, and t is the time in years.  For us:

P = 5200,

r = .046,

n = 365, and

t = 11

A(t)=5200(1+\frac{.046}{365})^{(365)(11)} and

A(t)=5200(1+.000126)^{4015} and

A(t)=5200(1.000126)^{4015} and

A(t) = 5200(1.658408042) so

A(t) = $8623.72

8 0
3 years ago
PET HOSPITAL The circle graph shows the types of pets treated at a pet hospital.
saul85 [17]
Sorry i need point
javausow
4 0
3 years ago
One type of ant weighs about 3 x 10^-3 gram. The ant can carry close to 1.5 x 10^-1 gram of food. The amount of food, in grams,
klemol [59]
You divide the amount the ant can carry by its weight to see how many time its own body weight it is carrying.  
(1.5x10^-1g)/(3x10^-3g)=5.0x10^1
=50 times their own body weight

(3x10^-3g)x50=0.15g (which 1.5x10^-1g)
I hope this helps.
4 0
3 years ago
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