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4 years ago

23) Write an equation in slope-intercept form that passes through (-4,-2) and has a slope of -9.

Mathematics

2 answers:

OLga [1]4 years ago

8 0

The slope intercept formula is:

y = mx + b

m is the slope

b is the y-intercept

This is the formula we have so far:

y = -9x + b

Now we must find b

To do that you must plug in the point the line goes through in the x and y of the equation.

(-4, -2)

-2 = -9(-4) + b

-2 = 36 + b

-38 = b

y = -9x - 38

Hope this helped!

~Just a girl in love with Shawn Mendes

Katen [24]4 years ago

7 0

Answer:

y=-9x-38

Step-by-step explanation:

In slope intercept form we know that the equation for a line is given by

y=mx+b, Where m is the slope (which we have and is -9) and b is the 'y' axis intercept point.

Lets use the given point (-4,-2) to find b

y=-2 and x=-4

-2=-9*-4 +b

We have b=-38

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Video Example EXAMPLE 1 Find the linearization of the function f(x) = x + 1 at a = 3 and use it to approximate the numbers 3.98

Blizzard [7]

Answer:

the linearization is y = 1/4x +5/4

the linearization will produce <em>overestimates</em>

the values computed from this linearization are ...

f(3.98) ≈ 2.245

f(4.05) ≈ 2.2625

Step-by-step explanation:

Apparently, you have ...

$f(x)=\sqrt{x+1}$

from which you have correctly determined that ...

$f'(x)=\dfrac{1}{2\sqrt{x+1}}$

so that f(3) = 2 and f'(3) = 1/4. Putting these values into the point-slope form of the equation of a line, we get the linearization ...

g(x) = (1/4)(x -3) +2

g(x) = (1/4)x +5/4

The values from this linearization will be overestimates, as the curve f(x) is concave downward everywhere. The tangent (linearization) is necessarily above the curve everywhere.

At the given values, we find ...

g(3.98) = 2.245

g(4.05) = 2.2625

4 0

4 years ago

Outside temperature over a day can be modelled as a sinusoidal function. Suppose you know the high temperature for the day is 10

WINSTONCH [101]

Answer:

The function for the outside temperature is represented by $T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right]$ , where t is measured in hours.

Step-by-step explanation:

Since outside temperature can be modelled as a sinusoidal function, the period is of 24 hours and amplitude of temperature and average temperature are, respectively:

Amplitude

$A = \frac{100\º-70\º}{2}$