23) Write an equation in slope-intercept form that passes through (-4,-2) and has a slope of -9.

Mathematics

2 answers:

OLga [1]4 years ago

8 0

The slope intercept formula is:

y = mx + b

m is the slope

b is the y-intercept

This is the formula we have so far:

y = -9x + b

Now we must find b

To do that you must plug in the point the line goes through in the x and y of the equation.

(-4, -2)

-2 = -9(-4) + b

-2 = 36 + b

-38 = b

y = -9x - 38

Hope this helped!

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Katen [24]4 years ago

7 0

Answer:

y=-9x-38

Step-by-step explanation:

In slope intercept form we know that the equation for a line is given by

y=mx+b, Where m is the slope (which we have and is -9) and b is the 'y' axis intercept point.

Lets use the given point (-4,-2) to find b

y=-2 and x=-4

-2=-9*-4 +b

We have b=-38

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Vaselesa [24]

Answer:

-3 comes from combining 1 and -4

Step-by-step explanation:

The -3 under the radical is the result of combining the terms

16 -4(16) = 16(1 -4) = 16(-3) = -3(16)

16 is factored out. It is done this way because 16 is a perfect square factor, so wants to maintain that identity while you figure out the rest of the radical.

$=\dfrac{-4\pm\sqrt{16-4(16)}}{2}=\dfrac{-4\pm\sqrt{16(1-4)}}{2}=\dfrac{-4\pm\sqrt{-3(16)}}{2}\\\\=\dfrac{-4\pm\sqrt{-3(4^2)}}{2}=\dfrac{-4\pm 4\sqrt{-3}}{2}=-2\pm2\sqrt{-3}=-2\pm2i\sqrt{3}$