The maximum height of the projectile is the maximum point that can be gotten from the projectile equation
The projectile reaches the maximum height after 5 seconds
The function is given as:

Differentiate the function with respect to t

Set to 0

So, we have:

Collect like terms


Solve for t


Hence, the projectile reaches the maximum after 5 seconds
Read more about maximum values at:
brainly.com/question/6636648
-24°F
Step-by-step explanation:
-18°F + 13°F - 19°F
= -5°F - 19°F
= -24°F
The rate of change of a function can be modeled with the following expression:

Where Δx is the change in x value, and Δk(x) is the corresponding change in k(x). We're given the two extremes of x, so we can calculate the change in x to be

To find the change in k(x), we can calculate the values of k(x) at x = -14 and x = -4 and find the difference between them:

So, the rate of change for the function from x = -14 to x = -4 is
Answer:
Pack of 6 apples for £1.65 is better because the price of 1 apple is less in this answer.
Both of the other angles are 40° because a triangle has a total angle of 180° and an isosceles triangle means that at least two of the sides have to be the same length (two angles must be the same)
180 - 100= 80
80 ÷ 2 = 40