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MatroZZZ [7]
3 years ago
5

What is three fractions equivalent to 3/11

Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0
3/11 *2 = 6/22
3/11 *3= 9/33
3/11 *4 = 12/44
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Someone help me with this please
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Answer:

A is 6 and B is 4

Step-by-step explanation:

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3 years ago
A bag of apples weighs 8 4 10 pounds. A crate of bananas is 5 times as heavy as the apples. How much heavier are the bananas tha
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3 years ago
Which of these groups of relative frequencies would be best represented by a pie chart?
SVETLANKA909090 [29]

All of these would be perfectly fine represented by a pie chart except A, which doesn't add to 100%.

The question seems to be getting at the idea that a pie chart might be better when the slices are all visually different sizes. I don't really think that's right; a pie chart for D say, where the two slices are about the same, gives the correct impression of the relative frequencies, which are about the same.

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7 0
3 years ago
What is the repulsive force between two pith balls that are 13.0 cm apart and have equal charges of −24.0 nC?
daser333 [38]

Answer:

The repulsive force is 3.067\times10^{-4}N.

Step-by-step explanation:

Consider the provided information.

The coulomb's law to calculate the repulsive force: F=\frac{kQ_1Q_2}{r^2}

Where the value of k is 9.00×10⁹ Nm²/C²

Substitute the respective values in the above formula.

F=\frac{9\times10^9\frac{N\cdot m^2}{c^2} \times(-24\times10^{-9}C)^2}{[(13 cm)(\frac{1m}{100cm} )]^2}

F=\frac{9\times10^9\frac{N\cdot m^2}{c^2} \times(-24\times10^{-9}C)^2}{(0.13 m)^2}

F\approx0.0003067N

F=3.067\times10^{-4}N

Hence, the repulsive force is 3.067\times10^{-4}N.

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(-3,-1)

Step-by-step explanatio

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3 years ago
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