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2 years ago

8

Eli used 2 1/5 liters of soup to completely fill 2 bottles. If the bottles are all the same size, how many liters of soup does e

ach bottle hold.

1 answer:

Mice21 [21]2 years ago

4 0

Answer:

the answer is 1 and 1/10th

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Simplify: StartRoot StartFraction 576 Over 64 EndFraction EndRoot The prime factorization of 576 is. The prime factorization of

riadik2000 [5.3K]

The prime factor of the 576 is $2^6 * 3^2$ and the prime factor of the 64 is $2^6$ . And the expression $\sqrt{\dfrac{576}{64}}$ is equal to 3.

<h3>What is simplification?</h3>

Simplification is to make something easier to do or understand and to make something less complicated.

Given

The expression is $\sqrt{\dfrac{576}{64}}$

The prime factor of the 576 will be

$576 = 2^6 * 3^2$

The prime factor of the 64 will be

$64 = 2^6$

Then the expression will be

$\sqrt{\dfrac{576}{64}} = \sqrt{\dfrac{2^6 * 3^2}{2^6}}\\\\\sqrt{\dfrac{576}{64}} = \sqrt{3^2}\\\\\sqrt{\dfrac{576}{64}} = 3$

More about the simplification link is given below.

brainly.com/question/12616840

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2 years ago

Tom has already baked 4 cakes, and he can bake 1 cake with each additional stick of butter he buys. How many additional sticks o

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since it takes 1 additional stick to bake a cake,then it takes 84 additional sticks to bake 42 cakes

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3 years ago

Smart about slopes help pls

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3 years ago

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Add the polynomials. Be sure to write your answer in standard form. (−4x3−5x+2)+(4x3+10)

Marat540 [252]

-5x+12 is the answer

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3 years ago

A geologist has collected 5 specimens of basaltic rock and 7 specimens of granite. The geologist instructs a laboratory assistan

MaRussiya [10]

The rocks are chosen without replacement, which means that the hypergeometric distribution is used to solve this question. First we get the parameters, and then we answer the questions. From this, we get that:

$E(X) = 5.25, Var(X) = 0.5966$
P(X < 6) = 0.9545
P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The mean and the variance are:

$\mu = \frac{nk}{N}$

$\sigma^2 = \frac{nk(N-k)(N-n)}{N^2(N-1)}$

We have that:

5 + 7 = 12 rocks, which means that $N = 12$

9 are chosen, which means that $n = 9$

7 are granite, which means that $k = 7$

Question a:

$E(X) = \mu = \frac{9\times7}{12} = 5.25$

$Var(X) = \sigma^2 = \frac{9\times7(12-7)(12-9)}{12^2(12-1)} = 0.5966$

Thus:

$E(X) = 5.25, Var(X) = 0.5966$

Question b:

Since there are only 5 specimens of basaltic rock, at least 9 - 5 = 4 specimens of granite are needed, which means that:

$P(X < 6) = P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 4) = h(4,12,9,7) = \frac{C_{7,4}*C_{5,5}}{C_{12,9}} = 0.1591$

$P(X = 5) = h(5,12,9,7) = \frac{C_{7,5}*C_{5,4}}{C_{12,9}} = 0.4773$

$P(X = 6) = h(6,12,9,7) = \frac{C_{7,6}*C_{5,3}}{C_{12,9}} = 0.3181$

Thus

$P(X < 6) = P(X = 4) + P(X = 5) + P(X = 6) = 0.1591 + 0.4773 + 0.3181 = 0.9545$

So P(X < 6) = 0.9545.

Question c:

5 of basaltic and 4 of granite: 0.1591 probability.

7 of granite is P(X = 7), in which

$P(X = 7) = h(7,12,9,7) = \frac{C_{7,7}*C_{5,2}}{C_{12,9}} = 0.0455$

0.1591 + 0.0455 = 0.2046, thus:

P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.

A similar question is found at brainly.com/question/24008577

5 0

3 years ago