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worty [1.4K]
2 years ago
8

Eli used 2 1/5 liters of soup to completely fill 2 bottles. If the bottles are all the same size, how many liters of soup does e

ach bottle hold.
Mathematics
1 answer:
Mice21 [21]2 years ago
4 0

Answer:

the answer is 1 and 1/10th

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If the measure of 0 is A radians and B degrees, then A=180B/pie
yKpoI14uk [10]
Yup that is correct, that is the way to convert measurements of angle from radians to degrees. because 2pi is equivalent to one revolution of a circle and in degrees is equal to 360 degrees, then simplifying it 360 / 2pi = 180 / pi.
so <span>the measure of 0 is A radians and B degrees, then A = 180 B/pi</span>
3 0
3 years ago
Solve 3x²-x-2=0. Please show all work.​
lorasvet [3.4K]

3x²-x-2=0

Δ=1+24=25 (Δ=b²-4ac)

x₁,₂=\frac{1(+/-)\sqrt{25} }{6}

x₁,₂=\frac{1(+/-)5}{6}

x1=\frac{1+5}{6}=6/6=1

x2=\frac{1-5}{6}=\frac{-2}{3}

so

x1=1

x2=\frac{-2}{3}

3 0
3 years ago
PLZZZZZZ HLPPPPP MEEEEEEE how could you find the y coordinate of the midpoint of a vertical line segment with endpoints at (0, 0
emmainna [20.7K]

Answer:

A. Add the endpoints

C. Divide -12 by 2

Step-by-step explanation:

To find the midpoint of the vertical line segment with endpoints (0, 0) and (0, -12).

Step 1: Add the endpoints (y-coordinates)

0+-12=-12

Step 2: Divide -12 by 2

-12/2=-6

Therefore, the y-coordinate of the midpoint of a vertical line segment is -6.

Options A and C are correct.

5 0
3 years ago
. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar
yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total <em>4+5+6 = 15 bulbs</em>. If we want to select 3 randomly there are  K ways of doing this, where K is the<em> combination of 15 elements taken 3 at a time </em>

K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

\frac{270}{455}=0.5934=59.34\%

(b)

The probability of selecting three 40-W bulbs is

\frac{4*3*2}{455}=0.0527=5.27\%

The probability of selecting three 60-W bulbs is

\frac{5*4*3}{455}=0.1318=13.18\%

The probability of selecting three 75-W bulbs is

\frac{6*5*4}{455}=0.2637=26.37\%

Since <em>the events are disjoint</em>, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

\frac{6*5*4}{455}=0.2637=26.37\%

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, <em>supposing there is no replacement</em>, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is \frac{9}{15}=0.6

Since there are no replacement, the probability of taking a second non 75-W bulb is now \frac{8}{14}=0.5714

Following this procedure 5 times, we find the probabilities

\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0
3 years ago
"-3x" + 5 &lt; "-10" Inequality 2: 7x + x - 4 &gt; 28 Which of the following values makes BOTH inequalities TRUE? Select all tha
zysi [14]

Answer:

12, 23, 48, 325

Step-by-step explanation:

So, when given two inequalities and asked to find the values that make both true, it is considered a system of equations. To solve a system of equation, you have to graph the inequalities and find where they intersect.

Inequality 1:

(-3x) + 5 < (-10)

Inequality 2:

7x + x - 4 > 28

simplifies to: 8x - 4 > 28

When graphed, the inequalities don't intersect, but rather have a similar shaded area overlapping from the point of 5 and greater.

Answers that apply from given list would be:

12, 23, 48, 325

6 0
3 years ago
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