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Alexxandr [17]
3 years ago
5

Mrs. Stampley has 30 pairs of shoes. She donates 2 pairs each month. Mr. Bonilla has 6 pairs of shoes. He purchases 4 pair each

month. After how many months, m, will they have the same amount of shoes?
Mathematics
1 answer:
vazorg [7]3 years ago
4 0

Answer:

4 months

Step by step explanation

If you subtract 30 by 2 for 4 months you get 22 and if you add 4 4 times to 6 you get 22 and that means the answer is 4 months.

You might be interested in
One hundred divided by twice a number is ten
Ludmilka [50]

\frac{100}{2x} = 10

Are you trying to find x, or are you only suppose to translate it?

If you are trying to find x, you first multiply 2x on both sides

100 = 10(2x)

Divide 10 on both sides

10 = 2x

Divide 2 on both sides

5 = x

5 0
3 years ago
Easy Multiple Choice Questions about expressions and linear equations / ASAP / Will mark brainliest / 25 Points
nata0808 [166]

Answer:

1.C

2.A

3.D

4.C

5.B

6.A

7.B

8.C

9.A

10. D

Step-by-step explanation:

For Problem 1, the work is as follows:

2(3x-1)+x\\Distribute\\6x-2+x\\7x-2

For Problem 2, the work is as follows:

(3x^{2} +6x+4) - (-x^{2} +2x-1)\\Distribute -\\(3x^{2} +6x+4) + (x^{2} -2x+1)\\Combine\\4x^{2} +4x+5

For Problem 3, the work is as follows:

5b-(a+c)^{2} \\5(3) - (-1+-4)^{2} \\15 - (-5)^{2} \\15-25\\-10

For Problem 4, the work is as follows:

4x-8 = -12\\+8\\4x = -4\\-4/4 = -1\\x = -1

For Problem 5, the work is as follows:

\frac{1}{2} (12x-6) = 2x-15\\Distribute\\\\6x - 3 = 2x -15\\+3\\6x = 2x -12\\-2x\\4x = -12\\-12/4\\x = -3

For Problem 6, the work is as follows:

17 *0.06 = 1.02\\17+1.02 = 18.02

For Problem 7, the work is as follows:

x = (2,0)\\y = (0,-1)\\\frac{rise}{run} \\y = \frac{1}{2} x-1

For Problem 8, the work is as follows:

y_{2} -y_{1} \\x_{2} -x_{1} \\-1-1 = -2\\0-(-2) = 2\\Slope = -1

For Problem 9, the work is as follows:

3y - 2x +6 = 0\\-3y\\(-3y - -2x+6)/-3\\y = \frac{2}{3} x -2

For Problem 10, the work is as follows:

(y-3) = -2(x-1)\\Distribute\\(y-3) = -2x+2\\+3\\y = -2x +5

Hope this Helps!

4 0
3 years ago
Simplify (1-6)(-4-7)​
lakkis [162]

Answer:

I’m guessing you subtract the numbers from the inside of the parenthesis and then multiply the two.

(-5)(-11) = 55

I hope this is correct.

7 0
3 years ago
George observes that for every increase of 1 in the value of x, there is a increase of 60 in the corresponding value of y. He cl
Brums [2.3K]

Hi there!

<u><em>FACTS</em></u><em> :</em>

<em>To see if multiple ratios are proportional, you can write them as fractions, reduce them, and compare them. If the reduced fractions are all the same, then you have proportionnal ratios. You can also write them as fractions and divide the numerator (top number) by its denominator (bottom number), and compare the decimal numbers the same way you would compare the fractions (I personnaly find this method easier because you don't need to simplify the fractions).</em>

<u>STEPS TO ANSWER:</u>

x = 1 ; y = 90 → \frac{1}{90} = 1 ÷ 90 = <u>0.01111111...</u>


x = 2 ; y = 150 → \frac{2}{150} = 2 ÷ 150 = <u>0.0133333...</u>


x = 3 ; y = 210 → \frac{3}{210} = 3 ÷ 210 = <u>0.01428571</u>


x = 4 ; y = 270 → \frac{4}{270} = 4 ÷ 270 = <u>0.0148148...</u>


x = 5 ; y = 330 → \frac{5}{330} = 5 ÷ 330 = <u>0.01515152</u>


<em>** You didn't really need to calculate them all because even the first two decimal numbers weren't equivalent, but I wanted to show you the whole process so I calculated them all.</em>


⇒ If you compare all the decimals you got, you can easily see that they are not the same, which means that the ratios between the values of "x" and the values of "y" are not proportional. Therefore, George's reasoning wasn't good.


There you go! I really hope this helped, if there's anything just let me know! :)

5 0
3 years ago
The table gives an inequality and a number to divide both sides of the inequality by. Identify the new, true inequality.
Daniel [21]

Answer:

A: -4 <-1

B: -2 < -1

C: 2> -5

D:2> -1

negative

Step-by-step explanation:

i did the assignment mark as brainliest?

5 0
2 years ago
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