So Since we know what b equals. We can just plug it into the equation b = 3 5a -10(3) = 45
First step is to solve -10(3) that means we multiply these two numbers. -10 x 3 = -30 Now plug that in for what it was in the equation.
5a - 30 = 45
Now the next step is to add 30 to both sides to cancel out -30
5a - 30 = 45 +30 = +30 *************** Now the 30's on the left side disappear and we solve on the right side. 45 + 30 = 75
Now set up your equation once again.
5a = 75
Now we divide both sides by 5 to isolate (or get a to be alone) 5a = 75 ÷5 = ÷5 ********* the 5's on the left side disappear and we solve on the right side.