A teacher is making identical activity packet using 92 Kranz and 23 sheets of paper what is the greatest number of packets the t
1 answer:
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Answer:
The Height of the tower is 188.67 ft
Step-by-step explanation:
Given as :
The angle of elevation to tower = 15°
The distance travel closer to tower the elevation changes to 42° = 497 ft
Now, Let the of height of tower = h ft
The distance between 42° and foot of tower = x ft
So, The distance between 15° and foot of tower = ( x + 497 ) ft
So, From figure :
<u>In Δ ABC </u>
Tan 42° =
Or , Tan 42° =
Or, 0.900 =
∴ h = 0.900 x
Again :
<u>In Δ ABD </u>
Tan 15° =
Or , Tan 15° =
Or, 0.267 =
Or, h = ( x + 497 ) × 0.267
So, from above two eq :
0.900 x = ( x + 497 ) × 0.267
Or, 0.900 x - 0.267 x = 497 × 0.267
So, 0.633 x = 132.699
∴ x =
Or, x = 209.63 ft
So, The height of tower = h = 0.900 × 209.63
Or, h = 188.67 ft
Hence The Height of the tower is 188.67 ft Answer
