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GalinKa [24]
3 years ago
7

A teacher is making identical activity packet using 92 Kranz and 23 sheets of paper what is the greatest number of packets the t

eacher can make with no items left over?
Mathematics
1 answer:
Yakvenalex [24]3 years ago
4 0
4 packets because you have to do 92/23 and you get 4.

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HELP ILL GIVE BRAINLIEST
Ksenya-84 [330]

Answer:

A: 40%

B: 75%

C: 90%

Step-by-step explanation:

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2 years ago
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The sum of two numbers is 50 and their difference is 4 what are the numbers
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Answer:

27 and 23

Step-by-step explanation:

x + y = 50

x - y = 4

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A suspension bridge has two main towers of equal height. A visitor on a tour ship
Scilla [17]

Answer:

The Height of the tower is 188.67 ft

Step-by-step explanation:

Given as :

The angle of elevation to tower = 15°

The distance travel closer to tower the elevation changes to 42° = 497 ft

Now, Let the of height of tower = h  ft

The distance between 42°  and  foot of tower = x  ft

So, The distance between 15° and  foot of tower =  ( x + 497 )  ft

So, From figure :

<u>In Δ ABC </u>

Tan 42° = \frac{perpendicular}{base}

Or , Tan 42° = \frac{AB}{BC}

Or,  0.900 = \frac{h}{x}

∴ h = 0.900 x

Again :

<u>In Δ ABD </u>

Tan 15° = \frac{perpendicular}{base}

Or , Tan 15° = \frac{AB}{BD}

Or,  0.267 = \frac{h}{( x + 497 )}

Or,  h = ( x + 497 ) × 0.267

So, from above two eq  :

     0.900 x =  ( x + 497 ) × 0.267  

Or, 0.900 x - 0.267 x =  497  × 0.267  

So, 0.633 x = 132.699

∴               x = \frac{132.699}{0.633}

Or,            x = 209.63  ft

So, The height of tower = h = 0.900 × 209.63

Or,                                      h = 188.67 ft

Hence The Height of the tower is 188.67 ft    Answer

3 0
2 years ago
Plsssss help plsssssss
Igoryamba
B is the correct answer.
7 0
3 years ago
PLZ HELP ME I NEED THIS ASAP
Andru [333]

Mean = 110

Sample size = 45

Standard deviation = 6

Z score for 90% is 1.645 ( from Z-table).

Lower Limit = Mean - Z(SD/√Sample size))

Lower limit = 110 - 1.645(6/√45)

Lower limit = 108.5

Upper Limit = Mean + Z(SD/√Sample size))

Lower limit = 110 +1.645(6/√45)

Lower limit = 111.5

The interval is (108.5, 111.5)

3 0
3 years ago
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