Answer:
x=9.4
x=9.43
Step-by-step explanation:
I used the Pythagorean theorem.
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1.BD=AC
AC^2=(9^2)+(6^2)-2(9)(6)COS115
AC^2=117-108COS115
AC=√71.358
AC=8.447//
Given: It is given that the length of the painting is 24 inches and the width is 11 inches.
To find: Area of the mat
Solution:
The watercolor painting is 24 inches long by 11 inches wide.
So, the area of the painting is:



The length of painting with mat is = 24 in + 3 in + 3 in = 30 in
The width of painting with mat = 11 in + 3 in + 3 in = 17 in


Now to calculate the area of mat subtracts the area of painting from the area of the mat.



Hence, the area of the mat is 246 in².
Answer:
critical value is 4.41
Step-by-step explanation:
Given data
n = 10
α = .05
to find out
the critical value
solution
first we calculate degree of freedom i.e
degree of freedom = n -1
degree of freedom = 10 - 1
degree of freedom = 9
and
degree of freedom 2 =( n -1 ) 2
degree of freedom 2 =( 10 -1 ) 2
degree of freedom 2 = 18
so for degree of freedom 9 and degree of freedom 2 is 18 and α = .05
critical value is 4.41