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Naddik [55]
4 years ago
15

Time zones around the world are either ahead (+) or behind (-) Greenwich Mean Time (GMT). If it is 9 p.m. in Greenwich, England,

what time would it be in Mumbai, India, which is five hours ahead of GMT? A) 4 a.m. B) 4 p.m. C) 2 p.m. D) 2 a.m.
Mathematics
2 answers:
jenyasd209 [6]4 years ago
8 0
The current GMT is 9:00 P.M.
The time in India is 5 hours more than GMT
5=3+2
9+3=12
12:00+ 2 hours= 2:00
Solution: D. 2 A.M.
Naddika [18.5K]4 years ago
3 0
Add 5 hours to 9pm and get 2 am
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If anyone can i help me
natulia [17]

Answer:

x=9.4

x=9.43

Step-by-step explanation:

I used the Pythagorean theorem.

Have a nice day!

and can I maybe have brainliest? Thanks!

3 0
3 years ago
Read 2 more answers
Construct a parallelogram ABCD such that AB=9 Cm, BC=6cm and ABC=115 degress.
kkurt [141]
1.BD=AC
AC^2=(9^2)+(6^2)-2(9)(6)COS115
AC^2=117-108COS115
AC=√71.358
AC=8.447//
3 0
3 years ago
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A watercolor painting is 24 inches long by 11 inches wide. Ramon makes a border around the watercolor painting by making a mat t
sergeinik [125]

Given: It is given that the length of the painting is 24 inches and the width is  11 inches.

To find: Area of the mat

Solution:

The watercolor painting is 24 inches long by 11 inches wide.

So, the area of the painting is:

\text{Area of painting}=l\times b

\text{Area of painting}=24\times 11

\text{Area of painting}=264 \text{ in}^2

The length of painting with mat is = 24 in + 3 in + 3 in = 30 in

The width of painting with mat = 11 in + 3 in + 3 in = 17 in

\text{Area of painting with mat}=30\times 17

\text{Area of painting with mat}=510 \text{ in}^2

Now to calculate the area of mat subtracts the area of painting from the area of the mat.

\text{Area of mat}=\text{Area of painting with mat}-\text{Area of painting}\\

\text{Area of mat}=510-264

\text{Area of mat}=246 \text{ in}^2

Hence, the area of the mat is 246 in².

6 0
3 years ago
At a pet store, Davina counted 12 parrots out of 20 birds. Which is an equivalent ratio of parrots to birds at the pet store? 2:
Mazyrski [523]

Answer:

3 to 2

Hope it helps xD

3 0
3 years ago
Read 2 more answers
For an independent-measures ANOVA comparing two treatments with a sample of n = 10 in each treatment, what is the critical value
trapecia [35]

Answer:

critical value is 4.41

Step-by-step explanation:

Given data

n = 10

α = .05

to find out

the critical value

solution

first we calculate degree of freedom i.e

degree of freedom = n -1

degree of freedom = 10 - 1

degree of freedom = 9

and

degree of freedom 2 =( n -1 ) 2

degree of freedom 2 =( 10 -1 ) 2

degree of freedom 2 = 18

so for degree of freedom 9 and degree of freedom 2 is 18  and α = .05

critical value is 4.41

4 0
3 years ago
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