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Sindrei [870]
3 years ago
7

Y= r/sqrt(r^2+1) Find y'

Mathematics
1 answer:
Ivan3 years ago
3 0
Well the SQRT and the ^2 cancel out on the R's so y=1 is whats left over
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Plz help me NOW and I will mark you brainliest
Readme [11.4K]

Answer:

Translate from words to mathematical equation.

"n is m% of what?"

m% = m/100

what = a variable ... "x". for example.

"is" means "="

"of" means multiply

n = (m/100)•x

5 0
2 years ago
One line passes through the points (-7,5)
Studentka2010 [4]

Answer:

1. (-7, 5 ) and (-1, 3)

(3-5)/(-1+7)= -2/6 = -1/3

y - 5 = (-1/3)(x + 7)

y - 5 = (-1/3)x - 7/3

y - 15/3= (-1/3)x - 7/3

y = (-1/3)x + 8/3

2. (-1-3)/(3-0)= -4/3

y + 3 = (-4/3)(x + 1)

y + 3 = (-4/3)x - 4/3

y + 9/3 = (-4/3)x - 4/3

y = (-4/3)x + 5/3

the answer is neither

7 0
3 years ago
hello! i struggle with math A LOT so if u guys can help me with these questions with the work i would appreciate a lot
elena-s [515]
Pretty sure 1 is 6/8
4 0
4 years ago
Read 2 more answers
Help wit this? 10m-8m+2+10
GenaCL600 [577]

Answer:

2m+12

Step-by-step explanation:

add like terms

2m+12

7 0
3 years ago
If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95​% confident that the d
katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Sample size needed

At least n, in which n is found when M = 0.09

We don't know the proportion, so we use \pi = 0.5, which is when we would need the largest sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.09\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.09}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}

n = 118.6

Rounding up

We need a sample size of least 119

6 0
3 years ago
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