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3 years ago

Given that 110ₓ = 40₅ , find the value of x.

Mathematics

1 answer:

MrRa [10]3 years ago

3 0

Answer:

x = 4

Step-by-step explanation:

110ₓ = 40₅ --------- change all to base ten.

<u>the system called binary</u>

1x²+1x ¹+0x⁰ = 45¹+0*5⁰

x² + x + 0 = 20

x² + x – 20 = 0

solve x using Quadratic equation

-1 ± $\sqrt{1^2 - 4* 1 (-20)}$

x = ------------------------------------

2 * 1

x = -5; x = 4

therefore, x = 4

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You want to test your newly created Web site, so you have 250 people access it from random locations at random times. Of the peo

Arte-miy333 [17]

Answer: 505

Step-by-step explanation:

The formula to find the sample size n , if the prior estimate of the population proportion (p) is known:

$n= p(1-p)(\dfrac{z}{E})^2$ , where E= margin of error and z = Critical z-value.

Let p be the population proportion of crashes.

Prior sample size = 250

No. of people experience computer crashes = 75

Prior proportion of crashes $p=\dfrac{75}{250}=0.3$

E= 0.04

From z-table , the z-value corresponding to 95% confidence interval = z=1.96

Required sample size will be :

$n=0.3(1-0.3)(\dfrac{1.96}{0.04})^2$ (Substitute all the values in the above formula)

$n= (0.21)(49)^2= 0.21\times2401$

$n= 504.21\approx505$ (Rounded to the next integer.)

∴ Required sample size = 505

6 0

3 years ago

(X+5)(x-3) Find the product

Allisa [31]

Answer:

(x-3) (x+5) => x*x+5x-3x-15

=> x*x+2x-15

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

HELP.... square root of y5

dmitriy555 [2]

Sqrt (y^4 * y)
Sqrt y*4 = y^2
y^2 sqrt y

4 0

3 years ago

The answer to this problem?

LenaWriter [7]

The simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

<h3>How to simplify the expression?</h3>

The expression is given as:

$\sqrt{\frac{162x^9}{2x^{27}}}$

Divide 162 and 2 by 2

$\sqrt{\frac{81x^9}{x^{27}}}$

Take the square root of 81

$9\sqrt{\frac{x^9}{x^{27}}}$

Apply the quotient rule of indices

$9\sqrt{\frac{1}{x^{27-9}}}$

Evaluate the difference

$9\sqrt{\frac{1}{x^{18}}}$

Take the square root of x^18

$\frac{9}{x^9}$

Hence, the simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$