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Mashutka [201]
4 years ago
13

I NEED HELP PLEASE, THANKS! :)

Mathematics
1 answer:
dedylja [7]4 years ago
5 0

Answer:  see below

<u>Step-by-step explanation:</u>

sin\ \theta=\dfrac{y}{r}=\dfrac{84}{85}\qquad \qquad \text{Quadrant I implies both x and y are positive}\\\\\\\\\text{Use Pythagorean Theorem to find x:}\\x^2+\ y^2=r^2\\x^2+84^2=85^2\\x^2\qquad =85^2-84^2\\x^2\qquad =169\\.\qquad x =13\\

Input x = 13, y = 84, r = 85 into the trig functions:

\sin\ \theta=\dfrac{y}{r}=\large\boxed{\dfrac{84}{85}}\qquad \qquad \qquad \csc \theta=\dfrac{r}{y}=\large\boxed{\dfrac{85}{84}}\\\\\\\\\cos\ \theta=\dfrac{x}{r}=\large\boxed{\dfrac{13}{85}}\qquad \qquad \qquad \sec \theta=\dfrac{r}{x}=\large\boxed{\dfrac{85}{13}}\\\\\\\\\tan\ \theta=\dfrac{y}{x}=\large\boxed{\dfrac{84}{13}}\qquad \qquad \qquad \cot \theta=\dfrac{x}{y}=\large\boxed{\dfrac{13}{84}}

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