3 years ago

HELP ASAP ASAP PLEASE

Mathematics

2 answers:

boyakko [2]3 years ago

7 0

Answer:

Many solutions

Step-by-step explanation:

pantera1 [17]3 years ago

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One solution
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A scientist is growing bacteria in a lab for study. One particular type of bacteria grows at a rate of y=2t^2+3t+500. A differen

Leya [2.2K]

ANSWER

Approximately after 15 minutes.

EXPLANATION

The growth rate of the first bacteria is

$y = 2 {t}^{2} + 3t + 500$

The growth rate of the first bacteria :

$y = 3 {t}^{2} + t + 300$

To find the time that, there will be an equal number of bacteria, we equate the two equation;

$3 {t}^{2} + t + 300 = 2 {t}^{2} + 3t + 500$

$3 {t}^{2} - 2 {t}^{2} + t - 3t + 300 - 500 =00$

${t}^{2} - 2t - 200= 0$

We solve for t to get,

$t = 15.177$

$t = - 13.177$

We discard the negative value.

This implies that,

$t \approx15$

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