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Kruka [31]
3 years ago
13

A gallon of moo milk costs $5.12. what is the unit price of an 8 ounces of moo milk

Mathematics
1 answer:
taurus [48]3 years ago
8 0

Answer:

$.32 per 8 ounces

Step-by-step explanation:

We know that 1 gallon = 128 ounces

To find the cost per ounce, we take the cost of 1 gallon ($5.12 and divide by 128)

5.12/128

$.04 per ounce

Now we have 8 ounces

We multiply the cost per ounce by the number of ounces

.04 *8

$.32 per 8 ounces

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Ron walks 0.5 miles on track in 10 minutes Stevie was 0.25 mile on the track in6 minutes find the unit rate for each walker in m
Leya [2.2K]

Answer:

Ron is the faster walker ; Ron = 3mph |  Stacie = 2.5mph

Step-by-step explanation:

To find per hour it is easy since both are factors of 60

(0.5*6)/(10*6) = 3mph

(0.25*10)/(6*10) = 2.5mph


5 0
3 years ago
Susan rides her bicycle 5 miles in 2/5 of an hour .at this rate how many miles could she ride in 2 hours
Oksi-84 [34.3K]
Divide 5 by 2 = 2.5 per 1/5 an hour
there are 10 of 1/5 an hour in 2 hours
so 10 X 2.5 = 25 miles in 2 hours
6 0
4 years ago
Read 2 more answers
(PLESE HELP) Factor the following expression. Simplify your answer.
mars1129 [50]

The factor of the expression 5p(p + 2)^{\frac{2}{3} }  + 4(p + 2)^{\frac{1}{3} } is(p + 2)^{\frac{2}{3} } (5p^{3}  + 10p^{2}  + 20p + 4)

To answer the question, we need to know what factorization is

<h3>What is factorization?</h3>

Factorization is the process of breaking down an expressing into a simpler form containing its factors.

Since

5p(p + 2)^{\frac{2}{3} }  + 4(p + 2)^{\frac{1}{3} }

Since (p + 2)^{\frac{1}{3} } is common, we factor it out. So, we have

(p + 2)^{\frac{2}{3} } (5p(p + 2)^{2}  + 4)

Expanding the bracket, we have

(p + 2)^{\frac{2}{3} } (5p(p^{2}  + 2p + 4) + 4) = (p + 2)^{\frac{2}{3} } (5p^{3}  + 10p^{2}  + 20p + 4)

So, the factor of the expression 5p(p + 2)^{\frac{2}{3} }  + 4(p + 2)^{\frac{1}{3} } is(p + 2)^{\frac{2}{3} } (5p^{3}  + 10p^{2}  + 20p + 4)

Learn more about factorization here:

brainly.com/question/11579257

#SPJ1

8 0
2 years ago
Question:
aivan3 [116]

Answer:

part A) The scale factor of the sides (small to large) is 1/2

part B) Te ratio of the areas (small to large) is 1/4

part C) see the explanation

Step-by-step explanation:

Part A) Determine the scale factor of the sides (small to large).

we know that

The dilation is a non rigid transformation that produce similar figures

If two figures are similar, then the ratio of its corresponding sides is proportional

so

Let

z ----> the scale factor

\frac{CB}{C'B'}=\frac{CD}{C'D'}=\frac{BD}{B'D'}

The scale factor is equal to

z=\frac{CB}{C'B'}

substitute

z=\frac{4}{8}

simplify

z=\frac{1}{2}

Part B) What is the ratio of the areas (small to large)?

<em>Area of the small triangle</em>

A=\frac{1}{2}(2)(4)=4\ units^2

<em>Area of the large triangle</em>

A=\frac{1}{2}(4)(8)=16\ units^2

ratio of the areas (small to large)

ratio=\frac{4}{16}=\frac{1}{4}

Part C) Write a generalization about the ratio of the sides and the ratio of the areas of similar figures

In similar figures the ratio of its corresponding sides is proportional and this ratio is called the scale factor

In similar figures the ratio of its areas is equal to the scale factor squared

4 0
4 years ago
PLEASE HELP ASAP! WILL MARK BRAINLIEST!
SCORPION-xisa [38]
Y+y-3 is the expression need to find the triangle's area
5 0
3 years ago
Read 2 more answers
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