Split up the interval [0, 2] into 4 subintervals, so that
![[0,2]=\left[0,\dfrac12\right]\cup\left[\dfrac12,1\right]\cup\left[1,\dfrac32\right]\cup\left[\dfrac32,2\right]](https://tex.z-dn.net/?f=%5B0%2C2%5D%3D%5Cleft%5B0%2C%5Cdfrac12%5Cright%5D%5Ccup%5Cleft%5B%5Cdfrac12%2C1%5Cright%5D%5Ccup%5Cleft%5B1%2C%5Cdfrac32%5Cright%5D%5Ccup%5Cleft%5B%5Cdfrac32%2C2%5Cright%5D)
Each subinterval has width
. The area of the trapezoid constructed on each subinterval is
, i.e. the average of the values of
at both endpoints of the subinterval times 1/2 over each subinterval
.
So,


Answer:
0.448 seconds
Step-by-step explanation:
d = -16t² -4t + 412
find t when d = 407
substituting d = 407 into the equation:
407 = -16t² -4t + 412 (subtract 407 from both sides)
-16t² -4t + 412 - 407 = 0
-16t² -4t + 5 = 0 (multiply both sides by -1)
16t² + 4t - 5 = 0
solving using your method of choice (i.e completing the square or using the quadratic equation), you will end up with
t = (-1/8) (1 + √21)= -0.70 seconds (not possible because time cannot be negative)
or
t = (-1/8) (1 -√21) = 0.448 seconds (answer)
Answer:
8x + 13
Step-by-step explanation:
"Like terms" means the same kind of algebraic expression...the 6x and the 2x are "like terms" because they both have an x in them. The 9 and the 4 are both constants, which means they are plain numbers. So 6x and 2x is 8x .
9+4 is 13 just like elementary school.
So all together,
6x + 9 + 2x + 4
6x + 2x + 9 + 4
8x + 13
We can rearrange the terms because the problem has all addition in between the terms.
Digit 3 on the 10 side has a value of 3 tens or 30. We want to find the digit that has exactly 10 times that value. well, 10 × 30 = 300. So which digit has the value of 300? The other 3 is in the 100's place and it's value is 3 one hundreds or 300. So that is your digit... the 3 in the hundreds place.
Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
we know that
A composite function is a function that depends on another function. A composite function is created when one function is substituted into another function
we have


Part 1) Determine f(g(x))
To find f(g(x)) substitute the function g(x) as the variable in function f(x)
so

Part 2) Determine g(f(x))
To find g(f(x)) substitute the function f(x) as the variable in function g(x)
so

For x=5

