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Bogdan [553]
4 years ago
15

What is the discriminant of the given equation ? X^2-2x+2+0 a)-12 b)8 c)-4 d)-8

Mathematics
1 answer:
Neporo4naja [7]4 years ago
8 0
∆= b^2 - 4ac

where b= -2
a=1
c=2

therefore: 2^2 - 4 x 1 x 2
= 4 - 4 x 2
= 4 - 8
= -4
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Alvin throws the football to a receiver who jumps up to catch the ball. The height of the ball over time can be represented by t
Mandarinka [93]

Answer:

The standard form of the equation is 49t² - 75t + 3 = 0

The solution of the equations are 1.49 and 0.041

Step-by-step explanation:

* Lets explain how to solve the problem

- The standard form of the quadratic equation is ax² + bx + c  = 0,

  where a , b , c are constant and a can not be 0

∵ The quadratic equation is -4.9t² + 7.5t + 1.8 = 2.1

- Lets make the left hand side equal to 0

∵ -4.9t² + 7.5t + 1.8 = 2.1 ⇒ subtract 2.1 from both sides

∴ -4.9t² + 7.5t - 0.3 = 0 ⇒ multiply each term by -10

∴ 49t² - 75t + 3 = 0

* The standard form of the equation is 49t² - 75t + 3 = 0

∵ ax² + bx + c = 0

∴ a = 49 , b = -75 , c = 3

- Lets use the formula x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a} to solve

 the equation

∴ x=\frac{-(-75)+\sqrt{(-75)^{2}-4(49)(3)}}{2(49)}=1.49

∴ x=\frac{-(-75)-\sqrt{(-75)^{2}-4(49)(3)}}{2(49)}=0.041

* The solution of the equations are 1.49 and 0.041

6 0
3 years ago
On a certain​ river, a paddleboat travels 12 miles upstream ​(against the​ current) in the same amount of time it travels 20 mil
marin [14]

Given :

a paddle boat travels  upstream = 12 miles

a paddle boat travels  downstream = 20 miles

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We know the distance for upstream D= (boat speed - current speed) * time

the distance for downstream D= (boat speed + current speed) * time

Plug in all the values and variables in the distance

For upstream 12 = (x-2)t, then t = \frac{12}{x-2}

For downstream 20 = (x+2)t then t = \frac{20}{x+2}

we got two equations for t, equate it and solve for x

\frac{12}{x-2} = \frac{20}{x+2}

Cross multiply it

12(x+2) = 20(x-2)

12x + 24 = 20x - 40 (subtract 12x  and add 40 on both sides)

64 = 8x

x= 8

the speed of the boat in still water = 8 miles per hour



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