2 years ago

Grade 10 math help please show work (30 points) I will mark brainlist too

Mathematics

1 answer:

dybincka [34]2 years ago

4 0

Answer:

5) ∅ =3.94°

6) ∅ = 22.19°

Step-by-step explanation:

5) tan ∅ = 3.9/56.67

tan ∅ = 0.0688

∅ =3.94°

6) cos ∅ = 250/270 (500/2 = 250)

cos ∅ = 0.9259

∅ = 22.19°

You might be interested in

PLEASE HELP, I’LL GIVE BREAINLIST!

zzz [600]

Answer:

1/72

Step-by-step explanation:

Not entirely sure but i do hope it helps

5 0

3 years ago

Read 2 more answers

The ampitude/frequency/period of y=1/4cos1/2x is 4 pie

Fantom [35]

Amplitude: 1/4 (= |a|)
Frequency: 1/2 (= |b|)
Period: 4pi (= 2pi/|b|)

7 0

3 years ago

Will pick brainliest if ur answer is correct

Gnesinka [82]

Answer:

Step-by-step explanation:

Hopefully this helps

6 0

2 years ago

Read 2 more answers

Subtract --4x2 + 3x - 7 from 8x2 + 2x - 3

r-ruslan [8.4K]

Answer:

Steps ig

((8x2) +2x(-3)))-(((-(-4)) x 2) +( 3 x( -7)) =23

5 0

3 years ago

19. A quadratic equation is shown below.

victus00 [196]

Answer:

$\{\sqrt b, -\sqrt b\}$

Step-by-step explanation:

Given

$a^2 - b = 0$

Required

Determine the solution

Since b is a perfect square, the equation can be expressed as:

$a^2 - (\sqrt b)^2 = 0$

Apply difference of two squares:

$(a - \sqrt b)(a + \sqrt b) = 0$

Split:

$(a - \sqrt b)= 0 \ or\ (a + \sqrt b) = 0$

Remove brackets:

$a - \sqrt b= 0 \ or\ a + \sqrt b = 0$

Make a the subject in both equations

$a =\sqrt b \ or\ a =-\sqrt b$

The solution can be represented as:

$\{\sqrt b, -\sqrt b\}$

6 0

2 years ago