Answer:
At a certain pizza parlor,36 % of the customers order a pizza containing onions,35 % of the customers order a pizza containing sausage, and 66% order a pizza containing onions or sausage (or both). Find the probability that a customer chosen at random will order a pizza containing both onions and sausage.
Step-by-step explanation:
Hello!
You have the following possible pizza orders:
Onion ⇒ P(on)= 0.36
Sausage ⇒ P(sa)= 0.35
Onions and Sausages ⇒ P(on∪sa)= 0.66
The events "onion" and "sausage" are not mutually exclusive, since you can order a pizza with both toppings.
If two events are not mutually exclusive, you know that:
P(A∪B)= P(A)+P(B)-P(A∩B)
Using the given information you can use that property to calculate the probability of a customer ordering a pizza with onions and sausage:
P(on∪sa)= P(on)+P(sa)-P(on∩sa)
P(on∪sa)+P(on∩sa)= P(on)+P(sa)
P(on∩sa)= P(on)+P(sa)-P(on∪sa)
P(on∩sa)= 0.36+0.35-0.66= 0.05
I hope it helps!
Answer:
2m + 10n - 2p
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
(4m + 7n - 6p) - (2m - 3n - 4p)
<u>Step 2: Simplify</u>
- Distribute negative: 4m + 7n - 6p - 2m + 3n + 4p
- Combine like terms (m): 2m + 7n - 6p + 3n + 4p
- Combine like terms (n): 2m + 10n - 6p + 4p
- Combine like terms (p): 2m + 10n - 2p
Answer:
5.23×10^5
Step-by-step explanation:
You mean 56.23×10^4?
That would be 5.623×10×10^4, or 5.23×10^5
Answer:
the third side is 4.
Step-by-step explanation:
Using Pythagorean theorem of a^2 + b^2 = c^2 for right triangles, substitute
the numbers to show (
+
=
and solve for b. The square root and square cancel each other out, so you get 65 +
= 81.
Subtract 65 from both sides to get
= 16.
Then take the square root of both sides to get b =
which equals 4.
Scalene triangles. I think