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nikitadnepr [17]
3 years ago
14

Help this is my last grade of the year and I need to do good

Mathematics
1 answer:
mixer [17]3 years ago
4 0

Answer:

The volume is 58.64.

<em>I hope this helps you out :)</em>

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Solve the system of linear equations -3x+5=13 and x+4y=-10
kari74 [83]

Answer:

(−8/3,−11/6)

Step-by-step explanation:

-3x+5=13 ; x+4y=-10

x=−8/3

and y=−11/6

6 0
3 years ago
Read 2 more answers
8,000 is invested in two different accounts earning 3% and 4% interest. If the two accounts earn a total of $295 in interest, ho
lesya692 [45]

Answer:

$5,500

Step-by-step explanation:

Let A be the amount invested at 3%, B the amount at 4%.

Total value:

1.A%2BB=8000

Interest:


Multiply eq. 1 by -3 and add to eq. 2,

-3A-3B%2B3A%2B4B=-24000%2B29500

highlight%28B=5500%29

Then from eq. 1,

A%2B5500=8000

highlight%28A=2500%29

3 0
3 years ago
Read 2 more answers
Annette has 5more dimes than quarters, the total amount is $3.30. How many of each coin does she have?
faust18 [17]

A


Step-by-step explanation:the answer is you have 8 quarter and 13 dimes .

Because you have 5 more dimes than quarters which will equal 3 dollars and 30 cents


7 0
3 years ago
Help please! This really impacts my grade!! Hope you guys know the answers
Leokris [45]

Answer: this dose not even make sense

Step-by-step explanation:

You only put a pdf

5 0
3 years ago
F(x) = lnx/x
My name is Ann [436]
f(x) = \frac{lnx}{x}

(a) f'(x) = \frac{d}{dx}[\frac{lnx}{x}]
Using the quotient rule:
f'(x) = \frac{\frac{1}{x} \cdot x - lnx}{x^{2}}
f'(x) = \frac{1 - lnx}{x^{2}}

For maximum, f'(x) = 0;
\frac{1 - lnx}{x} = 0
lnx = 1, x = e

(b) <em>Deduce:
</em>e^{x} \geq x^{e}, x > 0
<em>
Soln:</em> Since x = e is the greatest value, then f(e) ≥ f(x) > f(0)
\frac{ln(e)}{e} \geq \frac{lnx}{x}
\frac{1}{e} \geq \frac{lnx}{x}, since ln(e) is simply equal to 1

Now, since x > 0, then we don't have to worry about flipping the signs when multiplying by x.
\frac{x}{e} \geq lnx
x \geq elnx
x \geq ln(x^{e})

Taking the exponential to both sides will cancel with the natural logarithmic function in the right hand side to produce:
e^{x} \geq e^{ln(x^{e}})
e^{x} \geq x^{e}, as required.
3 0
3 years ago
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