Answer:
q = -1
Step-by-step explanation:
Solve for q:
15 - 3 (q - 4) = -5 (q - 7) - 10
-3 (q - 4) = 12 - 3 q:
12 - 3 q + 15 = -5 (q - 7) - 10
Grouping like terms, -3 q + 12 + 15 = (12 + 15) - 3 q:
(12 + 15) - 3 q = -5 (q - 7) - 10
12 + 15 = 27:
27 - 3 q = -5 (q - 7) - 10
-5 (q - 7) = 35 - 5 q:
27 - 3 q = 35 - 5 q - 10
Grouping like terms, -5 q - 10 + 35 = (35 - 10) - 5 q:
27 - 3 q = (35 - 10) - 5 q
35 - 10 = 25:
27 - 3 q = 25 - 5 q
Add 5 q to both sides:
5 q - 3 q + 27 = (5 q - 5 q) + 25
5 q - 5 q = 0:
5 q - 3 q + 27 = 25
5 q - 3 q = 2 q:
2 q + 27 = 25
Subtract 27 from both sides:
2 q + (27 - 27) = 25 - 27
27 - 27 = 0:
2 q = 25 - 27
25 - 27 = -2:
2 q = -2
Divide both sides of 2 q = -2 by 2:
(2 q)/2 = (-2)/2
2/2 = 1:
q = (-2)/2
The gcd of -2 and 2 is 2, so (-2)/2 = (2 (-1))/(2×1) = 2/2×-1 = -1:
Answer: q = -1
Answer:
The area is 16 inches squared and the perimeter is also 16 inches
Step-by-step explanation:
To find the area, you must multiply the length by the width. Since this is a square, you have to multiply one adjacent side by the other. For perimeter, you can either multiply one side by 4 or add all 4 sides.
Answer:
There is no distance between them
Step-by-step explanation:
For a 30 ft electric line to be placed between two 20ft electric poles, it would take 15 ft of the electric line to go down to about 5 ft above the ground and another 15 ft of the line to go to the top of the second electric pole. This means that a total of 30ft (15 ft + 15 ft) electric line would be needed which is all the cable we have.
For this to be possible then the poles must be adjacent to each other (i.e. no distance between them).
Answer:
14 1/2
Step-by-step explanation:
when you solve this equation you will get 14.5 which is 14 1/2.
I hope this helps you
Answer:
If in rectangular coordinates we have a point (x, y), then the angle defined between the x-axis and a ray that connects the point with the origin is defined by:
Tan(θ) = y/x
Cos(θ) = x/(√(x^2 + y^2))
Sin(θ) = y/(√(x^2 + y^2))
Ctg(θ) = x/y
Sec(θ) = √(x^2 + y^2)/x
Csc(θ) = √(x^2 + y^2)/y
Ok, now we have all the equations.
We know that:
Sec(C) = 30/24
Then:
√(x^2 + y^2) = 30
x = 24
Replacing x in the first equation we get:
√(24^2 + y^2) = 30
y = √(30^2 - 24^2) = 18
Then we have:
x = 24
y = 18
√(x^2 + y^2) = 30
So we can just replace these in the equations:
Tan(C) = y/x = 18/24
Cos(C) = x/(√(x^2 + y^2)) = 24/30
Sin(C) = y/(√(x^2 + y^2)) = 18/30
Ctg(θ) = x/y = 24/18
Sec(θ) = √(x^2 + y^2)/x = 30/24
Csc(θ) = √(x^2 + y^2)/y = 30/18
