Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
Answer:
All real numbers greater than 0
Step-by-step explanation:
When you look at y = log (2) x
Base 2, exponent y.
x = 2^y
x can only be a positive number.
Answer: The first option
Step-by-step explanation:
I'm smart
Using the number line below, draw a box and whisker plot for the following data: 12,18,18,20,22,22,25,26,30,30,32,32,35,35,38,49
Dmitry_Shevchenko [17]
Answer:
Step-by-step explanation:
Population size: 17
Median: 30
Minimum: 12
Maximum: 49
First quartile: 21
Third quartile: 35
Interquartile Range: 14
Outliers: none
Answer:
10 inches
Step-by-step explanation:
They're 36 degrees, so corresponding angles are the same, so the middle line is parallel to the bottom line of the triangle.
But the middle line bisects one of the waist lines of the triangle, so this is the middle line, which is equal to half the length of the bottom line
