Answer:
The flagpole's shadow is 16.875 feet longer than the man's shadow
Step-by-step explanation:
The total length of the shadow is expressed by taking its actual length by a factor that depends on the position of the sun which is constant for the man too. The expression is as follows;
Height of the shadow=actual height of the flagpole×factor
where;
length of the flagpole's shadow=22.5 feet
actual height of the flagpole=32 feet
factor=f
replacing;
22.5=32×f
32 f=22.5
f=22.5/32
f=0.703125
Using this factor in the expression below;
Length of man's shadow=actual height of man×factor
where;
length of man's shadow=m
actual height of man=8 feet
factor=0.703125
replacing;
length of man's shadow=8×0.703125=5.625 feet
Determine how much longer the flagpole's shadow is as follows;
flagpoles shadow-man's shadow=22.5-5.625=16.875 feet
The flagpole's shadow is 16.875 feet longer than the man's shadow
5 treats divided by six groups of one dog, or in easier terms, five dog treats divided up for 6 dogs. As a fraction, just remove the words except for 5, divided by, and 6, to give you 5/6. Hope this helped.
the discriminant is a negative value, thus no solution for such quadratic, meaning if we use h=64.5 like we did, there's no "t" seconds at which point the ball hits the batting cage.
Answer:
The first answer is correct.
Step-by-step explanation:
Line 5 says that the reason is due to substitution
Line 3 says m∠ SQT equals 180°
If we substitute 180° into the spot for m∠ SQT in line 4, we get solution option 1
Answer:
62
Step-by-step explanation:
IM NOT SURE I THINK BUT hope this helps :)
