For a quadratic function ƒ(x)=ax2+bx+c, ƒ(−1)<1, ƒ(1)>−1, and ƒ(3)<−4. What could be the sign of a?
1 answer:
Answer:
"a" must be negative
Step-by-step explanation:
The slope between points (-1, 1) and (1, -1) is a minimum of (-1-1)/(1-(-1)) = -1.
The slope between points (1, -1 and (3, -4) is a maximum of (-4-(-1))/(3-1) = -3/2.
Thus, as x increases, the slope is decreasing. In order for that to be the case, the value of <em>a</em> must satisfy a < 0.
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The surface to be paint is 4 * 12*8.5= 408 ft squared
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x= 408/75= 5,44 gallons