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just olya [345]
4 years ago
12

What's a simplest form for 6/12

Mathematics
2 answers:
pochemuha4 years ago
6 0
A simplest form is 1/2
2 can go into 6/12 and you would get 3/6 , you can simplify this again by 3 and get 1/2
siniylev [52]4 years ago
5 0
1/2 because 6 and 12 are divisible by 6
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Need help ASAP PLEASE !!!
max2010maxim [7]

Answer:

B.(-6,-1)

Step-by-step explanation:

4 0
3 years ago
A student used the equation below to create a table. y = –3x – 5 The student used –2 as one of the values for the input. Which o
Angelina_Jolie [31]

The ordered pair that could be taken from the table is: C. (–2, 1).

<h3>Ordered pairs of a Table</h3>

Ordered pairs are given as, (x, y). To find either x or y of a pair given an equation, plug in the given given to find the corresponding missing value of the ordered pair.

Input value = x-values, while output value = y-values.

Given:

y = –3x – 5

Let's find the corresponding y-value (output) of x = -2.

Substitute x = -2 into y = –3x – 5.

y = –3(-2) – 5

y = 6 - 5

y = 1

Therefore, the ordered pair that could be taken from the table is: C. (–2, 1).

Learn more about ordered pairs on:

brainly.com/question/1528681

7 0
3 years ago
State If the two triangles are congruent. If they are, state why.
Temka [501]
Yes these triangles appear congruent, they are equal in size and length
4 0
3 years ago
Read 2 more answers
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
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4 years ago
A dog groomer wants to gather information about how often dog owners have their dogs groomed. She decides to take
weeeeeb [17]

Answer:

a systematic random sample

6 0
3 years ago
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