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3 years ago

Please help ASAP will name brainliest

Mathematics

1 answer:

katen-ka-za [31]3 years ago

5 0

I would say it’s 1yd, it’s too small to be 2yds.
What answer did you put and get wrong the first try?

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How do I solve it. I don't understand where I should start the problem I have the formulas

Luda [366]

V=length times width times height
wait, we need it in yards
3ft=1yard
so height=1

v=45 times 30 times 1
v=1350 cubic yards
1 cubic yard=201.974 gallons
so times both sides by 1350
272664.9 gallons
per every 5000 gallons of water we have 1 of chlorine
so 272664.9/5000=54.53298
so we need about 54.5 gallons or 55 gallons of cholrine

4 0

3 years ago

9. If f(x)=-2x^2+4x-6, then f(2)=

Romashka-Z-Leto [24]

Answer:

f(2) = -6

General Formulas and Concepts:

Order of Operations: BPEMDAS

Substitution and Evaluation

Step-by-step explanation:

Step 1: Define

f(x) = -2x² + 4x - 6

f(2) is x = 2

Step 2: Solve

Substitute: f(2) = -2(2)² + 4(2) - 6
Exponents: f(2) = -2(4) + 4(2) - 6
Multiply: f(2) = -8 + 8 - 6
Add: f(2) = -6

3 0

3 years ago

Please be correct !!!!!!!!!!!!!!!!!xx

givi [52]

$2,022.92 would be the answer

5 0

3 years ago

Read 2 more answers

Given the system of linear equations.

Degger [83]

Part(A):

To solve the system of Linear equations using Substitution:

$x+y=7 \\ 2x+y=5$

Consider the first equation, x+y=7 implies x=7-y

$\mathrm{Subsititute\:}x=7-y$

$2\left(7-y\right)+y=5$

$14-2y+y=5$

$14-y=5$

$\mathrm{Subtract\:}14\mathrm{\:from\:both\:sides}$

$14-y-14=5-14$

$-y=-9$

$\mathrm{Divide\:both\:sides\:by\:}-1$

$y=9$

$\mathrm{For\:}x=7-y$

$\mathrm{Subsititute\:}y=9$

$x=7-9=-2.$ $\mathrm{The\:solutions\:to\:the\:system\:of\:equationts\:are:}$

$y=9,\:x=-2$

PArt(B): Use a graph to verify your answer to the system:

Using Desmos graphing calculator, graph the two equations.

8 0

3 years ago

Read 2 more answers

Rotate the axes to eliminate the xy-term in the equation. Then write the equation in standard form.

kirill115 [55]

Answer:

$\dfrac{x'^2}{2}-\dfrac{y'^2}{2}=1$

Step-by-step explanation:

The rotation by angle $\theta$ formulas are

$\left\{\begin{array}{l}x=x'\cos \theta-y'\sin \theta\\y=x'\sin \theta+y' \cos \theta\end{array} \right.$

To eliminate the xy-term, we have to rotate by 45°, so

$\left\{\begin{array}{l}x=x'\cos 45^{\circ}-y'\sin 45^{\circ}\\y=x'\sin 45^{\circ} +y' \cos 45^{\circ}\end{array} \right.$

$\left\{\begin{array}{l}x=x'\dfrac{\sqrt{2}}{2}-y'\dfrac{\sqrt{2}}{2}\\y=x'\dfrac{\sqrt{2}}{2} +y' \dfrac{\sqrt{2}}{2}\end{array} \right.$

Substitute them into the equation $xy+1=0:$

$\left(x'\dfrac{\sqrt{2}}{2}-y'\dfrac{\sqrt{2}}{2}\right)\cdot \left(x'\dfrac{\sqrt{2}}{2}+y'\dfrac{\sqrt{2}}{2}\right)+1=0\\ \\\left(x'\dfrac{\sqrt{2}}{2}\right)^2 -\left(y'\dfrac{\sqrt{2}}{2}\right)^2+1=0\\ \\\dfrac{x'^2}{2}-\dfrac{y'^2}{2}=1$

8 0

3 years ago