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galina1969 [7]
2 years ago
11

Hi can anyone help me do this question,I will mark brainlest.​

Mathematics
1 answer:
saul85 [17]2 years ago
4 0

Answer:

11. 40.5

12. 84

Step-by-step explanation:

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Find the sum of -3x square- 4x +3 and 2x square -x +3​
Lady_Fox [76]

Answer:

−x²−4x+3−x+3

Subtract x from −4x.

−x²−5x+6

Step-by-step explanation:

4 0
3 years ago
Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the
motikmotik

<u>Given</u>:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

<u>Coordinates of the point A':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point A(-2,3), we get;

(-2,3)\rightarrow (-2,-3)

Thus, the coordinates of the point A' is (-2,-3)

<u>Coordinates of the point B':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point B(0,3), we get;

(0,3)\rightarrow (0,-3)

Thus, the coordinates of the point B' is (0,-3)

<u>Coordinates of the point C':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point C(-1,-1), we get;

(-1,-1)\rightarrow (-1,1)

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

8 0
3 years ago
98 Points !! These are follow up according to previous question that had been answered for me. Help would be appreciated ! :))
IgorLugansk [536]
That's a copy of the figure from the other post; I didn't look at the answer.

We have Start(0,0)

A(-16.55\cos 25, -16.55 \sin 25)

B=A+(5 \cos 53, 5 \sin 53)

C=B+(20,0)

C=(-16.55\cos 25 + 5 \cos 53+20, -16.55 \sin25 - 5 \sin 53)

C \approx (8.00968, -10.9875) \approx(8,-11)

Your team takes the direct path at a constant speed of 6 miles per hour.

<span>Our team.  T=\sqrt{8^2+11^2}/6 = 2.27 \textrm{ hours}

</span><span>Team Red follows the riddle and travels at 8 mph from Start to Post A, 9 mph from Post A to Post B, and 11 mph from Post B to Finish.

T=16.55/8 + 5/9 + 20/11 = 4.44 \textrm{ hours}

Team Blue follows the riddle and travels at a constant speed of 10 mph.

</span>T=(16.55 + 5 + 20)/10 = 4.155 \textrm{ hours}
<span>
Team Yellow follows the riddle and travels at a constant speed of 11 mph, but stops at Post A for 30 minutes and stops again at Post B for another 30 minutes.
</span>
T=(16.55 + 5 + 20)/11 + 30/60 + 30/60=4.78 \textrm{ hours}

Winner: our team, then Blue, then Red, then Yellow

<span>
</span>

3 0
3 years ago
The length of the hypotenuse of a 30-60-90 triangle is 9. What is the perimeter?
denis23 [38]
The perimeter of any figure, is all its sides summed up

now, notice the picture below, using the 30-60-90 rule, that's "x"

now, get the other sides, since you know what "x" is, and sum them up, that's the perimeter

5 0
2 years ago
Read 2 more answers
What is the point-slope form with the slope -6 and the line through (1,-4)?
lakkis [162]

Answer:

y-(-4)=-6(x-1)

its is either (x-1), or (x+1). Im not sure on the last part

Step-by-step explanation:

hope this helps :3

if it did pls mark brainliest

8 0
2 years ago
Read 2 more answers
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