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poizon [28]
3 years ago
5

What formula most likely exists in D18?

Computers and Technology
1 answer:
gavmur [86]3 years ago
4 0
<span>Cystagia from Dynamic Nutritionals is a homeopathic UTI, bladder and kidney support that promotes urinary tract health and function.</span>
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Write a program that teaches arithmetic to a young child. The program tests addition and subtraction. In level 1, it tests only
Elenna [48]

Answer:

Explanation:

The following program is written in Java and creates three levels with the different set of randomly generated arithmetic problems. As the player goes getting more points they advance every 5 points to the next level.

import java.util.Random;

import java.util.Scanner;

class Main {

   private static Random random = new Random();

   private static Scanner in = new Scanner(System.in);

   static int points = 0;

   public static void main(String[] args) {

       while (true) {

           System.out.println(points);

           if (points < 5) {

               System.out.println("Starting Level 1");

               levelOne();

           } else if (points < 10) {

               System.out.println("Starting Level 2");

               levelTwo();

           } else if (points < 15) {

               System.out.println("Starting Level 3");

               levelThree();

           }

       }

   }

   public static boolean levelOne() {

       int numberOne = random.nextInt(10);

       int numberTwo = random.nextInt((10 - numberOne));

       int answer = numberOne + numberTwo;

       int count = 0;

       while (points < 5 && count < 2) {

           System.out.println("What is " + numberOne + " + " + numberTwo + "?: ");

           int userChoice = in.nextInt();

           if (userChoice == answer) {

               points += 1;

               levelOne();

           } else {

               count += 1;

           }

       }

       return false;

   }

   public static boolean levelTwo() {

       int numberOne = random.nextInt(10);

       int numberTwo = random.nextInt(10);

       int answer = numberOne + numberTwo;

       int count = 0;

       while (points < 10 && count < 2) {

           System.out.println("What is " + numberOne + " + " + numberTwo + "?: ");

           int userChoice = in.nextInt();

           if (userChoice == answer) {

               points += 1;

               levelTwo();

           } else {

               count += 1;

           }

       }

       return false;

   }

   public static boolean levelThree() {

       int numberOne = random.nextInt(10);

       int numberTwo = random.nextInt(10);

       int answer = numberOne - numberTwo;

       int count = 0;

       if (answer <= 0) {

           levelThree();

       }

       while (points < 15 && count < 2) {

           System.out.println("What is " + numberOne + " - " + numberTwo + "?: ");

           int userChoice = in.nextInt();

           if (userChoice == answer) {

               points += 1;

               levelThree();

           } else {

               count += 1;

           }

       }

       return false;

   }

}

3 0
3 years ago
Select the answer that best describes the ethical guideline followed in each scenario.
Montano1993 [528]
We need the scenario to solve this feel free to comment on this with your so scenarios and I will provide you with answers or just post another question
4 0
3 years ago
Design an algorithm to generate the sequence of positive integers (In increasing order) whose only prime divisors are 2 and 3.
Natasha2012 [34]

Answer:

es muy buena pero es muy difícil que ni yo pude entender

8 0
3 years ago
Ok so this isn’t really a question that is for school but...
Nastasia [14]

Answer:

u shoud just keep it ;-;

Explanation:

5 0
3 years ago
Assume that source elements of length k are mapped in some uniform fashion into a target elements of length p. If each digit can
lukranit [14]

Answer And explanation

a)

r^k has 1/r^k probability guess the correct source

b)

Each element in r^p  is mapped by r^k / r^p . There are r^k^-^p  So there are  r^k^-^p -1 elements.

number of target elements = r^k^-^p

number of source elements = r^k^-^p -1

probability = r^k^-^p -1 /r^k

c) Probability of the correct target element

1/r^p

6 0
3 years ago
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