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MA_775_DIABLO [31]
3 years ago
14

8. Point O is the circumcenter of the triangle ABC shown below.

Mathematics
1 answer:
Gnoma [55]3 years ago
8 0

Answer:

Option B. perpendicular bisector of side AB

Step-by-step explanation:

we know that

The circumcenter is the intersection point of the perpendicular bisectors of a triangle  

so

In this problem

The circumcenter O is the intersection point of perpendicular bisector of side AB and perpendicular bisector of side BC

OA=OB=OC ------> the radius of the circle that passes through all three of the triangle's vertices.

therefore

Option B. perpendicular bisector of side AB

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Korvikt [17]

Answer:

Step-by-step explanation:

Alright so just like the other problem we have to use ratios to find if it is parallels or not. In order for AC and DE to be parallels the sides CE and AD and DB and EB have to have the same ration. So in answer c if you do 24/22.5 you would get 1.066666667. So then to find the length of EB we subtract 24 from 40 to get 16 and then we do 16/15 to find out if the ratios are the same. And indeed they are the same both equaling 1.066666667. If you were to divide CE/AD and DB/EB none of the answers would be the same leading to c being the correct answer

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Bezzdna [24]

Answer:

\frac{2}{3} , \frac{27}{64}

Step-by-step explanation:

Volume: length* height * width

In the first diagram:

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Next diagram:

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The volume is \frac{27}{64} cubic yards

3 0
2 years ago
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What is the order of these numbers from least to greatest?<br><br> 4.03 4.3 4.003
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The order is 4.003 then 4.03 then 4.3
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In the triangle below, what ratio is sin θ? right triangle with sides whose lengths are 5, 12, and 13; angle theta is opposite t
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If you sketch the triangle, you need to understand that 12 is the length of opposite side (opposite to theta). Then the longest side is 13 is the hypotenuse. The other side with length 5 is the adjacent side. Thus from the definition of sin(theta)=opposite side/hypotenuse=12/13. A question for you, what is cos(theta)? cos(theta)=5/15 and tan(theta)=12/5
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Alja [10]

Answer:

6, 2, 2/3, 2/9, 2/27, 2/81

Step-by-step explanation:

The nth term of a geometric progression is expressed as;

Tn  = ar^n-1

a is the first term

n is the number of terms

r is the common ratio

Given

a = 6

r = 1/3

when n = 1

T1 = 6(1/3)^1-1

T1 = 6(1/3)^0

T1 = 6

when n = 2

T2= 6(1/3)^2-1

T2= 6(1/3)^1

T2 = 2

when n = 3

T3 = 6(1/3)^3-1

T3= 6(1/3)^2

T3= 6 * 1/9

T3 = 2/3

when n = 4

T4 = 6(1/3)^4-1

T4= 6(1/3)^3

T4= 6 * 1/27

T4 = 2/9

when n = 5

T5 = 6(1/3)^5-1

T5= 6(1/3)^4

T5= 6 * 1/81

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when n = 6

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T6= 6(1/3)^5

T6= 6 * 1/243

T6 = 2/81

Hence the first six terms are 6, 2, 2/3, 2/9, 2/27, 2/81

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2 years ago
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