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andrew11 [14]
3 years ago
14

PLEASE HELP ME!¡!¡!¡ :)))

Mathematics
1 answer:
jonny [76]3 years ago
7 0
I think the answer is c because there is no pattern and linear has to have a pattern so nonlinear doesn't have a pattern. Thats why the answer is c.
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Abigail has $356 in her bank account. She earns simple interest on her money at a rate of 3% per year for a total of five years.
fredd [130]

Answer:

it's probably b

Step-by-step explanation:

I don't know how to do it so don't do b

7 0
3 years ago
13 more than 4 times a number is negative 91 how would i find the number?
alekssr [168]
<span>13 more than 4 times a number is negative 91 

</span>Convert to numbers: 


13 more than 4: 4+13

times a number: (x)

is negative 91: = -91

Put it together: 

4x+13=-91

                   x = -26

                  



5 0
3 years ago
Read 2 more answers
Help plsssss .......
kondaur [170]

Answer:

B

Step-by-step explanation:

Matches all specified equations.

7 0
2 years ago
(-2q^4)(-8q^3b^6)<br>help I need to simplify this problem
Montano1993 [528]
Multiply the constants. Multiply the variables according to the rules of exponents.
(-2q^{4})(-8q^{3}b^{6}) = ((-2)(-8))q^{(4+3)}b^{6}\\\\=16q^{7}b^6}
4 0
3 years ago
Please help! thanks so much​
Stels [109]

Answer:

See below.

Step-by-step explanation:

First, we can see that \lim_{x \to 2}  (f(x))= -1.

Thus, for the question, we can just plug -1 in:

\lim_{x \to 2} (\frac{x}{f(x)+1})=\frac{(2)}{-1+1}  =und.

Saying undefined (or unbounded) will be correct.

However, note that as x approaches 2, the values of y decrease in order to get to -1. In other words, f(x) will always be greater or equal to -1 (you can also see this from the graph). This means that as x approaches 2, f(x) will approach -.99 then -.999 then -.9999 until it reaches -1 and then go back up. What is important is that because of this, we can determine that:

\lim_{x \to 2} (\frac{x}{f(x)+1})=\frac{(2)}{-1+1}  = +\infty

This is because for the denominator, the +1 will always be greater than the f(x). This makes this increase towards positive infinity. Note that limits want the values of the function as it approaches it, not at it.

4 0
3 years ago
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