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3 years ago

PLEASE HELP ME!¡!¡!¡ :)))

1 answer:

7 0

I think the answer is c because there is no pattern and linear has to have a pattern so nonlinear doesn't have a pattern. Thats why the answer is c.

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Help,anyone can help me do quetion,I will mark brainlest.

vichka [17]

Answer:

Step-by-step explanation:

B3)

z + 127 = 180 {linear pair}

z = 180 - 127

z = 53

y= 55 {Corresponding angles}

w + z + y = 180 {angle sum property of triangle}

w + 53 + 55 = 180

w + 108 = 180

w = 180 -108

w = 72

x = w {Vertiaclly opposite angles}

x = 72

B4) q + 101 = 180 {Linear pair}

q = 180 -101

q = 79

p = 142 {Corresponding angles}

p + s = 180 {linear pair}

142 + s = 180

s = 180 - 142

s = 38

s +q +r = 180 {angle sum property of triangle}

38 + 79 + r = 180

117 + r = 180

r = 180 - 117

r = 63

y + 63 = 180 {linear pair}

y = 180 - 63

y = 117

x = q = {corresponding angles}

x = 79

5 0

3 years ago

Help me with this please. Thanks!

horsena [70]

Cubic inch.
Proszę.
Myślę że pomoglem.

7 0

4 years ago

A player of a video game is confronted with a series of opponents and has an 80% probability of defeating each one. Success with

Vikentia [17]

Answer:

(a) The PMF of X is: $P(X=k)=(1-0.20)^{k-1}0.20;\ k=0, 1, 2, 3....$

(b) The probability that a player defeats at least two opponents in a game is 0.64.

(d) The probability that a player contests four or more opponents in a game is 0.512.

(e) The expected number of game plays until a player contests four or more opponents is 2.

Step-by-step explanation:

Let X = number of games played.

It is provided that the player continues to contest opponents until defeated.

(a)

The random variable X follows a Geometric distribution.

The probability mass function of X is:

$P(X=k)=(1-p)^{k-1}p;\ p>0, k=0, 1, 2, 3....$

It is provided that the player has a probability of 0.80 to defeat each opponent. This implies that there is 0.20 probability that the player will be defeated by each opponent.

Then the PMF of X is:

$P(X=k)=(1-0.20)^{k-1}0.20;\ k=0, 1, 2, 3....$

(b)

Compute the probability that a player defeats at least two opponents in a game as follows:

P (X ≥ 2) = 1 - P (X ≤ 2)

= 1 - P (X = 1) - P (X = 2)

$=1-(1-0.20)^{1-1}0.20-(1-0.20)^{2-1}0.20\\=1-0.20-0.16\\=0.64$

Thus, the probability that a player defeats at least two opponents in a game is 0.64.

(c)

The expected value of a Geometric distribution is given by,

$E(X)=\frac{1}{p}$

Compute the expected number of opponents contested in a game as follows:

$E(X)=\frac{1}{p}=\frac{1}{0.20}=5$

Thus, the expected number of opponents contested in a game is 5.

(d)

Compute the probability that a player contests four or more opponents in a game as follows:

P (X ≥ 4) = 1 - P (X ≤ 3)

= 1 - P (X = 1) - P (X = 2) - P (X = 3)

$=1-(1-0.20)^{1-1}0.20-(1-0.20)^{2-1}0.20-(1-0.20)^{3-1}0.20\\=1-0.20-0.16-0.128\\=0.512$

Thus, the probability that a player contests four or more opponents in a game is 0.512.

(e)

Compute the expected number of game plays until a player contests four or more opponents as follows:

$E(X\geq 4)=\frac{1}{P(X\geq 4)}=\frac{1}{0.512}=1.953125\approx 2$

Thus, the expected number of game plays until a player contests four or more opponents is 2.

4 0

4 years ago

A bank account earns interest at a rate of 3.5% per year (in other words it increases in value by that percent) and starts with

Oduvanchick [21]

Answer:

Annually cumulating interest can be determined by the following formula:

W=P(1+r)^y

r represents the interest rate as a decimal, and P represents the starting amount of money.

Step-by-step explanation:

7 0

3 years ago

Area of triangle Question 4

Marat540 [252]

Answer:

3sq units

Step-by-step explanation:

bxh = 2x3=6

6/2=3

3 0

3 years ago