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denis23 [38]
2 years ago
12

Point A is at (6,-6) and point C is at (-6,-2). Find the coordinates of point B on line AC such that AB= 3/4 AC

Mathematics
1 answer:
nevsk [136]2 years ago
3 0

Answer:

-3, -3

Step-by-step explanation:

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Find an equation of the line that satisfies the given condition. (Let x be the independent variable and y be the dependent varia
NeTakaya

Answer:

y = 4

Step-by-step explanation:

  • A line parallel to the x-axis has the same value of the <em>dependent variable (y)</em> for all the values of the <em>independent variable (x)</em>.  Hence, the line would be an <u>horizontal line that  passes through the y-axis and never meets the x-axis</u>. Since this line satisfies the condition of passing through the coordenates (x,y), (-6,4), then the equation is equal to the value of the coordinate y.  

 

Therefore, the equation of a line that satisfies these two conditions is <em>y = 4</em>.

Download pdf
8 0
3 years ago
And airplanes at altitude change -370 ft over 7 minutes what was the mean change of altitude in feet per minute?
Reil [10]
We have that
<span> [the mean change of altitude]=[change in altitude]/[time]
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the answer is -52.86 ft/minute  (<span>the negative sign means that the plane is descending</span>)
3 0
3 years ago
Determine the measure of ∠Q, rounded to the nearest tenth of a degree.<br> images attached.
const2013 [10]

Answer:

D

Step-by-step explanation:

Using the Sine rule in Δ QRS , that is

\frac{q}{sinQ} = \frac{r}{sinR} , that is

\frac{15}{sinQ} = \frac{12}{sin50.1} ( cross- multiply )

12× sinQ = 15 × sin50.1° ( divide both sides by 12 )

sinQ = \frac{15sin50.1}{12} , thus

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8 0
3 years ago
Points (1,3), (-4,7), and (-29,K) are collinear. Find K.<br><br> How do i solve this?
oee [108]
Co linear points have same slope
<span>Points (1,3), (-4,7), and (-29,K)
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m2,3=K-7/-29+4
m2,3=K-7/-25

-4/5=K-7/-25
4/5=K-7/25
4=K-7/5
20=K-7
K=27
 </span>
3 0
3 years ago
What is the area of the octagon?
Anna007 [38]

Answer:

A=2(1+2)a2

Step-by-step explanation:

8 0
3 years ago
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