All categories

3 years ago

6x − 3y = 42 6x + 8y = 20

Mathematics

1 answer:

san4es73 [151]3 years ago

5 0

Answer:

X= 6, y= -2

Step-by-step explanation:

Let 6x-3y=42------------(1)

6x + 8y =20---------(2)

Subtract (1) from (2) we have

(2) - (1)

6x-6x + 8y - (-3y) = 20 -42

11y = -22

y = -22/ 11 = -2

From (1)

6x - 3y =42

6x - 3(-2) = 42

6x + 6 = 42

6x = 42- 6

6x = 36

x= 36/6 = 6

You might be interested in

AB and BC are tangents to P. what is the value of x? this is really so confusing

Westkost [7]

1. Angle PAB is 90 degrees, as it is formed from the tanget to the circle at A, and the radius drawn to A.

2. AB=BC, because tangents drawn to a circle from the same point are equal.

3. PB is Common, so by the side-side-side congruence postulate, triangles ABP and CBP are congruent.

4. So measure of m(BPA)=x/2 and m(ABP)=73/2.

5. $\frac{x}{2}+90+ \frac{73}{2}=180$

$\frac{x+73}{2}=90$

$x+73=180$ , x= 107 degrees.

4 0

4 years ago

Standard for<br> ola (y + 3)2 = -12(x - 2), iden<br> 1.<br> D<br> n111

Vedmedyk [2.9K]

Answer:

See below

Step-by-step explanation:

Your question is a bit unclear, so I'm going to assume you want the value of y or x:

(y+3)^2=-12(x-2)

-(y+3)^2/12=x-2

-(y+3)^2/12+2=x

(y+3)^2=-12(x-2)

y+3=sqrt(-12x+24)

y=sqrt(-12x+24)-3

5 0

3 years ago

Sue has $2.10 in dimes and nickels. If she has 12 more dimes than nickels, how many of each coin does she have?

Andreas93 [3]

Sue would have 21 dimes and 12 less of 21 is 9, so sue has 9 nickels

dimes: 21
nickels: 9

8 0

3 years ago

What is the perimeter of a polygon with vertices at (−2, 1) , (−2, 4) , (2, 7) , (6, 4) , and (6, 1) ?

alekssr [168]

First we need the distances of the sides of the polygon, because perimeter = sum of all sides.
$d = \sqrt{{(y2 - y1)}^{2} + {(x2 - x1)}^{2} }$
$d1 = \sqrt{{(1 - 4)}^{2} + {( - 2 - - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3$
$d2 = \sqrt{{(4 - 7)}^{2} + {( - 2 - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {( -4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5$
$d3 \: = \sqrt{{(7 - 4)}^{2} + {(2 - 6)}^{2} } \\ = \sqrt{{(3)}^{2} + {( - 4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5$
$d4 = \sqrt{{(4 - 1)}^{2} + {(6 - 6)}^{2} } \\ = \sqrt{ {(3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3$
$d5 = \sqrt{{(1 - 1)}^{2} + {(-2 - 6)}^{2} } \\ = \sqrt{ {(0)}^{2} + {( - 4)}^{2}} = \sqrt{16} \: = 4$
Now, we add all sides for the perimeter:
p = d1 + d2 + d3 + d4 + d5
p = 3+5+5+3+4 = 20 units

5 0

3 years ago

Read 2 more answers

A group of students were asked if they like Math class and if they like English class.

padilas [110]

A if that’s wrong i’m vv sorry

5 0

3 years ago

Read 2 more answers