Question is Incomplete; Complete question is given below.
Which expressions are equivalent to 8 (negative 10 x + 3.5 y minus 7)? Select two options. Negative 80 x + 24.5 y minus 56 Negative 80 x + 28 y minus 56 80 x + 28 y + 56 4 (negative 20 x + 7 y minus 14) Negative 4 (negative 20 x + 7 y minus 14)
Answer:
Negative 80 x + 28 y minus 56
4 (negative 20 x + 7 y minus 14)
Step-by-step explanation:
Given:
We need to find the equivalent expression for given expression.
Solution:
First we will apply distributive property for given expression.
So we get;
Hence first expression equivalent to given expression is 
.
Now again evaluating the expression we get;
We will take 4 as common factor from the expression we get;
Hence second expression equivalent to given expression is 
.
Answer:
The correct answer is:
Poisson (A.)
Step-by-step explanation:
A Poisson distribution is used to model the number of events occurring within a given time interval, when the average number of times that the event occurs within the time interval is given.
Lambda ( λ ) is a rate parameter in Poisson's distribution, and it is used to represent "event/time", and it simply represents <em>the expected number of events in the interval.</em>
Answer: Summer Math Packet for Students Entering Algebra 2. 1. Percentages ... E) -15+6 = -9 f). 35:-7 = 5 g. 3[2(6+1)-32). 1+(22-1)+1. 1 = 3 h). 4:3 =
Step-by-step explanation: Good luck!
Answer:
<u>1</u><u>2</u>
2
Step-by-step explanation:
(3,7)(5,19)
(x,y)(x,y)
<u>y2</u><u>(</u><u>1</u><u>9</u><u>)</u><u>-</u><u> </u><u>y1</u><u>(</u><u>7</u><u>)</u>
x2(5)-x1 (3)
formula. <u>y2-y1</u>
x2-x1
Answer:
2°
Step-by-step explanation:
Hello
I see you are very confused by this problem. However, there is an easy way to solve this one.
It has been proved that the sum of all angles in a rectangle is always 180°. Here is a way to prove it:
x y
_______A_________
/\
/ \
/ \
/ \
___/_______ \__
B C
we have two parellel lines xy and BC. It is true that:
xAy = 180°
xAB + BAC + CAy = xAy = 180
xAB = ABC
CAy= ACB
=> ........
I'll let you finish with your great intellect ^_^
HOPE YOU LEARN WITH JOY AND GOOD GRADE
