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3 years ago

Find the zeros of g(x) = -x^2 + 6x - 8

Mathematics

1 answer:

lbvjy [14]3 years ago

3 0

(Remember to set g(x) to zero).

For this, I will be completing the square. Firstly, what two terms have a product of 8x^2 and a sum of 6x? That would be 4x and 2x. Replace 6x with 2x + 4x: $0=-x^2+2x+4x-8$

Next, factor -x^2 + 2x and 4x - 8 separately. Make sure that they have the same quantity on the inside of the parentheses: $0=-x(x-2)+4(x-2)$

Next, you can rewrite the equation as $0=(-x+4)(x-2)$

Now apply the Zero Product Property:

$-x+4=0\\-x=-4\\x=4\\\\x-2=0\\x=2$

<u>The zeros of this equation are 4 and 2.</u>

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What's the best definition of the word "ratio?"

ololo11 [35]

Answer:

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Step-by-step explanation:

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7 0

3 years ago

Kyle received the following course grades for 10 (three-credit) courses during his freshman year:

timofeeve [1]

Answer:

(a) The average grade point is 2.5.

(b) The relative frequency table is show below.

Step-by-step explanation:

The given data set is

4, 4, 4, 3, 3, 3, 1, 1, 1, 1

(a)

The average grade point is

$Average=\frac{\sum x}{n}$

$Average=\frac{4+4+4+3+3+3+1+1+1+1}{10}$

$Average=2.5$

Therefore the average grade point is 2.5.

(b)

$\text{Relative frequency}=\frac{\text{Frequency of number}}{\text{Total frequency}}$

The relative frequency table is show below:

x f Relative frequency

4 3 $\frac{3}{10}=0.3$

3 3 $\frac{3}{10}=0.3$

1 4 $\frac{4}{10}=0.4$

(c)

Mean of the relative frequency distribution is

$Average=\frac{0.3+0.3+0.4}{3}$

$Average=0.3333$

Therefore the mean of the relative frequency distribution is 0.3333.

4 0

3 years ago

The lifespans of gorillas in a particular zoo are normally distributed. The average gorilla lives 16 years; the

STatiana [176]

Using the Emperical rule:

68% lie with one one standard deviation:

16 + 1.7 , 16-1.7 = 17.7, 14.3

14.3 is part of the 68%.

The remaining 32% of the distribution is outside the range, with half being less than and half being greater than.

32/2 = 16

The probability of living loner than 14.3 Would be 16%

3 0

3 years ago

Based on historical data, your manager believes that 37% of the company's orders come from first-time customers. A random sample

fomenos

Answer:

0.6214 = 62.14% probability that the sample proportion is between 0.26 and 0.38

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

37% of the company's orders come from first-time customers.

This means that $p = 0.37$

A random sample of 225 orders will be used to estimate the proportion of first-time-customers.

This means that $n = 225$

Mean and standard deviation:

$\mu = p = 0.37$

$s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.37*0.63}{225}} = 0.0322$

What is the probability that the sample proportion is between 0.26 and 0.38?

This is the pvalue of Z when X = 0.38 subtracted by the pvalue of Z when X = 0.26.

X = 0.38

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.38 - 0.37}{0.0322}$

$Z = 0.31$

$Z = 0.31$ has a pvalue of 0.6217

X = 0.26

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.26 - 0.37}{0.0322}$

$Z = -3.42$

$Z = -3.42$ has a pvalue of 0.0003

0.6217 - 0.0003 = 0.6214

0.6214 = 62.14% probability that the sample proportion is between 0.26 and 0.38

5 0

3 years ago

4|n+8| = 56 <br><br>please help

Alchen [17]

To solve the absolute value equation you first need to get everything not in the absolute value bars to the other side of the equation.

Step 1) Divide by 4
|n+8| = 14

*Remember: when solving absolute value equations, you make what the expression (n+8) is equal to negative and positive. Not the other way around.

Step 2) Make two equations

n+8 = 14
n+8 = -14

Solve and you'll see that n= 6 and -22

3 0

3 years ago