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3 years ago

4|n+8| = 56 please help

1 answer:

3 0

To solve the absolute value equation you first need to get everything not in the absolute value bars to the other side of the equation.

Step 1) Divide by 4
|n+8| = 14

*Remember: when solving absolute value equations, you make what the expression (n+8) is equal to negative and positive. Not the other way around.

Step 2) Make two equations

n+8 = 14
n+8 = -14

Solve and you'll see that n= 6 and -22

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I don't know how to answer this question.

laiz [17]

Answer:

- 39/8y

Step-by-step explanation:

First you need to find a common denominator:

There is already a y in both denominators, so you don't have to worry about that. Since only one denominator has an 8, the other needs to have an 8, so you need to multiply the first fraction by 8 → - 4/y * 8 = - 32/8y

From here you can subtract the numerators:

- 32/8y +(- 7/8y) = - 39/8y

Because you are adding a negative to a negative, it makes the number mroe negative

I hope this helps!

3 0

3 years ago

Type the correct answer in each box. use numerals instead of words. students in a reading class have three options for their boo

Alexus [3.1K]

The answers to the questions on how she would use the colored chips are given here:

brochure 4 blue chips

writing a new article 6 yellow chips

designing a computer presentation 10 red chips

<h3>How to solve for the values</h3>

For the first percentage

20 / 100 = x/20

= 20 * 20 = 100x

400 = 100x

divide through by 100

x = 400/100

x = 4

For the second percentage

30/100 = x/20

600 = 100x

x = 600/100

x = 6

For the last

50/100 = x/20

1000 = 100x

x = 10

The proof is that 6 + 4 + 10 still gives us 20

Read more on percentages here: brainly.com/question/24877689

#SPJ1

4 0

2 years ago

8/x-5 - 9/x-4 = 5/x^2-9x+20

adelina 88 [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2752942

_______________

Solve the equation:

$\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}$

Reduce the fractions at the left side so that they have the same denominator:

$\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}$

Numerators must be equal:

$\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}$

I hope this helps. =)

Tags: <em>rational equation fraction solution algebra</em>

7 0

2 years ago

Kevin is solving this problem. 737 × 205 What are the partial products Kevin will need to solve the problem? A. 3,685 and 147,40

Andrew [12]

the answer is A

700 x 5 = 3500

30 x 5 = 150

7 x 5 = 35

3500 + 150 +35 = 3685

700 x 200 = 140,000

30 x 200 = 6000

7 x 200 = 1400

140000 + 6000 + 1400 = 147400

6 0

2 years ago

Use the graph method to solve the system of the linear equations:

Sophie [7]

Answer:

Step-by-step explanation:

I hope it's right

Sorry if it's wrong

6 0

2 years ago

Read 2 more answers