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3 years ago

4|n+8| = 56 please help

1 answer:

3 0

To solve the absolute value equation you first need to get everything not in the absolute value bars to the other side of the equation.

Step 1) Divide by 4
|n+8| = 14

*Remember: when solving absolute value equations, you make what the expression (n+8) is equal to negative and positive. Not the other way around.

Step 2) Make two equations

n+8 = 14
n+8 = -14

Solve and you'll see that n= 6 and -22

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In the diagram of circle C, what is the measure of 21?

kondaur [170]

Answer:

If I know what diagram you're referring to, which I believe I do, the answer is: ∠1=(1/2)[106°-36°]=35°

4 0

3 years ago

Brigitte is shorter than 5 feet. (Brigitte's height=h). Help please

KonstantinChe [14]

Brigitte is shorter than 5 feet. (Brigitte's height=h)

We write this in inequality form

Brigitte's height is h

So 'h' is shorter than 5 feet

Shorter means less than so we use < symbol. We should not use = symbol because height is shorter than 5 not equal to 5.

Suppose if it is given ' height is more than 5 feet ' then we use greater than symbol (>)

h is less than 5 feet

h < 5

Inequality is h < 5

3 0

3 years ago

Read 2 more answers

Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

The function is

$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

7 0

3 years ago

Is it A. B. C. or D.

podryga [215]

Your answer would be b i'm pretty sure

5 0

3 years ago

Which ratios form a proportion?

LekaFEV [45]

I would say D. 10/16, 5/8
Hope This helps :)

4 0

2 years ago