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kkurt [141]
3 years ago
14

Which characteristic could help you distinguish between types of fungi?

Biology
1 answer:
koban [17]3 years ago
3 0

Answer:

<em>A. The spores made by the fungi</em>

Explanation:

The major phyla of the fungi are usually classified on the basis of characteristics of sexual structures.

For instance, the chytridiomycota produce zoospores, the blastocladiomycota undergo sporic meiosis, the ascomycota forms ascospores et cetera.

Fungi are mainly classified into seven phyla:

Microsporidia

Chytridiomycota

Blastocladiomycota

Neocallimastigomycota

Glomeromycota

Ascomycota

Basidiomycota

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<span>D.) increased number of small crabs because fishing nets catch mostly large crabs
This situation is caused indirectly.</span>
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Tiny structures inside of cells, such as Ribosomes or chloroplasts that have specialized roles are called
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The tiny structures  inside of cells, such as Ribosomes or chloroplasts that have specialized roles are called organelles. These structures are found in the cytoplasm of eukaryotic cells and are enclosed with a membrane. These tiny structures are not present in prokaryotes like in bacteria. 
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1. Flower position, stem length, and seed shape are three characters that Mendel studied. Each is controlled by an independently
maria [59]

Answer:

a. 1/64 AATTDD

b. 1/64 aattdd

c. 8/64=1/8 AaTtDd

d. 2/64 = 1/32 AATTDd or aattDd or AAttDd or aaTTDd

Explanation:

<u>Available data:</u>

  • Flower position: Axial (A) is dominant to Terminal (a)
  • Stem length: Tall (T) is dominant to dwarf (t)
  • Seed shape: Round (R) is dominant to wrinkled (r)

<u>Cross</u>:

Parental) AaTtDd   x   AaTtDd

Knowing that these four genes assort independently, then we can infer that the F1 will have the next genotypic proportions for each gene:

  • AA= 1/4

       Aa =2/4

       aa = 1/4

  • TT = 1/4

        Tt = 2/4

         tt = 1/4

  • DD = 1/4

        Dd = 2/4

        dd = 1/4

<em>This is the same as developing a Punnett square for each gene separately.</em>

Knowing this, to get each of the mentioned genotypes for each trait, we must multiply their respective genotypic proportions, like this:

a. homozygous for the three dominant traits, AATTDD

   AA1/4 x TT 1/4 x DD 1/4 = AATTDD 1/64

b. homozygous for the three recessive traits, aattdd

   aa 1/4 x tt 1/4 x dd 1/4 = aattdd 1/64

c. heterozygous for all three characters, AaTtDd

   Aa 2/4 x Tt 2/4 x Dd 2/4 = AaTtDd 8/16=1/8

d. homozygous for axial and tall, heterozygous for seed shape. There are four possibilities, all of them with the same result:

AATTDd --> 1/4  x 1/4 x 2/4 = 2/64=1/32

aattDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

AAttDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

aaTTDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

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The correct answer is:

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